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authorpriyanka2015-06-24 15:03:17 +0530
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+
+clc
+//initialization of variables
+R = 0.082 // litre-atm/mol-K
+T = 283 // Kelvin
+V2 = 0.018 // litre/mol
+//For first solution contents are sucrose and water
+w1 = 0.01 // gm of sucrose
+MW1 = 342 // MW of sucrose
+w2 = 0.09 // gm of water
+MW2 = 18 // MW of water
+n1 = 1 // no of particles sucrose divides into in water
+//Calculations
+x1juice = (n1*w1/MW1)/((n1*w1/MW1)+(w2/MW2))// Mole fracion of sucrose
+//For second solution , contents are NaCl and water
+w1 = 35 // gm of NaCl
+MW1 = 58.5 // MW of Nacl
+w2 = 100 // gm of water
+MW2 = 18 // MW of water
+n1 = 2 // no of particles sucrose divides into in water
+//Calculations
+x1brine = (n1*w1/MW1)/((n1*w1/MW1)+(w2/MW2))// Mole fracion of sucrose
+//Calculation of difference in Osmotic pressure
+DeltaPi = (R*T/V2)*log((1-x1juice)/(1-x1brine))// atm
+//Results
+printf("The osmotic pressure difference is %.f atm",DeltaPi)
+//answer wrong in textbook
+