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authorpriyanka2015-06-24 15:03:17 +0530
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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Turbomachinery Design and Theory,Rama S. R. Gorla and Aijaz A. Khan, Chapter 3, Example 1")
+disp("Given data : Discharge rate Q = 145 l/s, Head H = 220m, U1 = U2 = 14m/s, beta2 = 180-160 =20degrees")
+Q = 145;
+H = 220;
+U2 = 14;
+U1 = U2;
+beta2 = 20;
+g = 9.81;
+disp("Refering figure")
+disp("Using Using Euler’s equation, work done per weight mass of water per sec.= (Cw1U1 - Cw2U2). But for Pelton wheel Cw2 is negative")
+disp("Therefore Work done / s = (Cw1U1 + Cw2U2) Nm / s. From inlet velocity triangle Cw1 = C1 and C1^2/2g = H")
+C1 = (2*g*H)^0.5
+disp("Relative velocity at inlet V1")
+V1 = C1-U1
+disp("From outlet velocity triangle")
+V2 = V1
+Cw2 = cos(20*%pi/180)*V2 -14
+disp("Hence, work done per unit mass of water per sec.")
+W = C1*U1+Cw2*U2
+disp("Power in kw")
+P = W*Q/1000