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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 8.7
+//Block Gauss-Seidel Method
+//Page no. 283
+clc;clear;close;
+
+A=[10,1,0,0,0,-1;1,10,1,0,0,0;2,0,20,1,0,0;0,0,1,10,-1,0;0,3,0,0,30,3;0,0,0,2,-2,20]; //equation matrix
+B=[5;10;10;0;0;5] //solution matrix
+disp(B,'B=',A,'A=')
+
+for i=1:2
+ for j=1:2
+ A11(i,j)=A(i,j);
+ end
+ B1(i,1)=B(i,1);
+end
+for i=1:2
+ for j=1:2
+ A12(i,j)=A(i,j+2);
+ end
+ B2(i,1)=B(i+2,1);
+end
+for i=1:2
+ for j=1:2
+ A13(i,j)=A(i,j+4);
+ end
+ B3(i,1)=B(i+4,1);
+end
+for i=1:2
+ for j=1:2
+ A21(i,j)=A(i+2,j);
+ end
+end
+for i=1:2
+ for j=1:2
+ A22(i,j)=A(i+2,j+2);
+ end
+end
+for i=1:2
+ for j=1:2
+ A23(i,j)=A(i+2,j+4);
+ end
+end
+for i=1:2
+ for j=1:2
+ A31(i,j)=A(i+4,j);
+ end
+end
+for i=1:2
+ for j=1:2
+ A32(i,j)=A(i+4,j+2);
+ end
+end
+for i=1:2
+ for j=1:2
+ A33(i,j)=A(i+4,j+4);
+ end
+end
+disp(B3,'B3=',B2,'B2=',B1,'B1=',A33,'A33=',A32,'A32=',A31,'A31=',A23,'A23=',A22,'A22=',A21,'A21=',A13,'A13=',A12,'A12=',A11,'A11=');
+A11_1=inv(A11);A22_1=inv(A22);A33_1=inv(A33);
+disp(A33_1,'Inverse of Matrix A33=',A22_1,'Inverse of Matrix A22=',A11_1,'Inverse of Matrix A11=');
+for i=1:2
+ X1(i,1)=0;
+ X2(i,1)=0;
+ X3(i,1)=0;
+end
+for i=1:6
+ X(i,1)=i-1;
+end
+for i=2:7
+ X(1,i)=0;
+end
+for r=1:5
+ X11=A11_1*(-1*A12*X2+(-1)*A13*X3+B1);
+ X22=A22_1*(-1*A21*X11+(-1)*A23*X3+B2);
+ X33=A33_1*(-1*A31*X11+(-1)*A32*X22+B3);
+ X1=X11;
+ X2=X22;
+ X3=X33;
+ disp(X3,'X3=',X2,'X2=',X1,'X1=')
+ for i=2:7
+ if(i<4)
+ X(r+1,i)=X1(i-1,1);
+ end
+ if(i<6 & i>3)
+ X(r+1,i)=X2(i-3,1);
+ end
+ if(i<8 & i>5)
+ X(r+1,i)=X3(i-5,1);
+ end
+ end
+end
+printf('\n\nIteration');
+for i=1:6
+ printf(' x%i ',i);
+end
+printf('\n --------------------------------------------------------------------------------')
+disp(X)
+printf('\n\nAfter 4 iterations exact solution is:\n');
+for i=1:6
+ printf('x%i=%f ',i,X(5,i+1));
+end \ No newline at end of file