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+//Example 8.6

+//Block Jacobi Method

+//Page no. 281

+clc;clear;close;

+

+A=[10,1,0,0,0,-1;1,10,1,0,0,0;2,0,20,1,0,0;0,0,1,10,-1,0;0,3,0,0,30,3;0,0,0,2,-2,20];        //equation matrix

+B=[5;10;10;0;0;5]                     //solution matrix

+disp(B,'B=',A,'A=')

+for i=1:3

+    for j=1:3

+        A11(i,j)=A(i,j);

+    end

+    B1(i,1)=B(i,1);

+end

+for i=1:3

+    for j=1:3

+        A12(i,j)=A(i,j+3);

+    end

+end

+for i=1:3

+    for j=1:3

+        A21(i,j)=A(i+3,j);

+    end

+end

+for i=1:3

+    for j=1:3

+        A22(i,j)=A(i+3,j+3);

+    end

+    B2(i,1)=B(i+3,1);

+end

+disp(B2,'B2=',B1,'B1=',A22,'A22=',A21,'A21=',A12,'A12=',A11,'A11=');

+A11_1=inv(A11);A22_1=inv(A22);

+disp(A22_1,'Inverse of A22=',A11_1,'Inverse of A11=')

+for i=1:3

+    X1(i,1)=0;

+    X2(i,1)=0;

+end

+for r=1:2

+    X11=A11_1*(-1*A12*X2+B1);

+    X22=A22_1*(-1*A21*X1+B2);

+    X1=X11;

+    X2=X22;

+    disp(X1,'X1=')

+    disp(X2,'X2=')

+end

+for i=1:6

+    if(i<4)

+        X(i,1)=X1(i,1);

+    else

+        X(i,1)=X2(i-3,1);

+    end

+end    

+disp(X,'X=')

+printf('\n\n\nNote : There is a computation error in calculation of X1(2)')

+    

+        

+