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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Example 19.10
+//Non Linear 1st Order Hyperboolic Differential Equation
+//Page no. 667
+clc;clear;close;
+
+c=-2;k=0.05;h=0.2;
+r=abs(c)*k/h;
+printf('\n i\t x\t|\tj -->\t')
+for i=0:6
+ printf(' %i\t',i)
+end
+printf('\n |\t |\t|\tt -->\t')
+for i=0:6
+ printf('%.3f\t',i*k)
+end
+i=1;
+x=0;
+printf('\n---------------------------------------------------------------------------------------')
+for j=1:7
+ for i=1:6
+ if j==1 then
+ u(i,j)=exp(-x);
+ u(i+1,j)=exp(-(x+h));
+ elseif i==1 then
+ u(i,j)=1
+ else
+ u(i,j)=u(i,j-1)-k*(u(i+1,j-1)^2-u(i-1,j-1)^2)/(4*h)+k^2*((u(i+1,j-1)+u(i,j-1))*(u(i+1,j-1)^2-u(i,j-1)^2)-(u(i,j-1)+u(i-1,j-1))*(u(i,j-1)^2-u(i-1,j-1)^2))/(8*h^2)
+ end
+ x=x+h
+ end
+end
+x=0;
+for i=1:6
+ printf('\n %i\t%.1f\t|\t\t',i-1,x)
+ for j=1:7
+ printf('%.3f\t',u(i,j))
+ end
+ x=x+h
+end \ No newline at end of file