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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+printf("\t example 19.3 \n");
+Qr=1.5; // Qr=(QF2/QF1)
+Cr=1.5; // Cr=(CR2/CR1)
+Gr=140/125; // Gr=(G2/G1)
+Qr1=0.38; // Qr1=(Q1/QF1)
+printf("\t approxiate values are mentioned in the book \n");
+a1=1.63; // a1=(G1*(CR1/27)^(1/2)), from eq 19.17
+printf("\t a1 is : %.2f \n",a1);
+a2=1.37*(a1); // a2=(G2*(CR2/27)^(1/2))
+printf("\t a2 is : %.2f \n",a2);
+Qr2=(1/(1+a2)); // Qr2=(Q2/QF2),from eq 19.15
+printf("\t Qr2 is : %.2f \n",Qr2);
+Q21=(Qr2/Qr1)*(Qr); // Q21=(Q2/Q1)
+printf("\t ratio of heats is : %.2f \n",Q21);
+printf("\t Hence the radiant absorption will be increased only 22 per cent for an increase of 50 per cent in the heat liberated. \n");
+// end
+