initial commit / add all books

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diff --git a/1328/CH12/EX12.5/12_5.sce b/1328/CH12/EX12.5/12_5.sce
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+printf("\t example 12.5 \n");

+printf("\t approximate values are mentioned in the book \n");

+T1=130; // inlet hot fluid,F

+T2=125; // outlet hot fluid,F

+T3=100; // after subcooling

+t1=80; // inlet cold fluid,F

+t3=100; // outlet cold fluid,F

+W=21000; // lb/hr

+w=167000; // lb/hr

+printf("\t 1.for heat balance \n");

+printf("\t for pentane \n");

+c=0.57; // Btu/(lb)(F)

+qs=((W)*(c)*(T2-T3)); // Btu/hr

+printf("\t total heat required for subcooling of pentane is : %.0e Btu/hr \n",qs);

+HT1=315; // enthalpy at T1, Btu/lb

+HT2=170; // enthalpy at T2, Btu/lb

+qc=(W*(HT1-HT2)); // for condensation

+printf("\t total heat required for condensing of pentane is : %.2e Btu/hr \n",qc);

+Q=qs+qc;

+printf("\t total heat required for  pentane is : %.2e Btu/hr \n",Q);

+printf("\t for water \n");

+c=1; // Btu/(lb)*(F)

+Q=((w)*(c)*(t3-t1)); // Btu/hr

+printf("\t total heat required for water is : %.2e Btu/hr \n",Q);

+deltw=18.2;

+printf("\t deltw is : %.1f F \n",deltw);

+t2=t3-deltw;

+printf("\t t2 is : %.1f F \n",t2)

+printf("\t for condensing \n");

+delt1=T2-t2; //F

+delt2=T1-t3; // F

+printf("\t delt1 is : %.0f F \n",delt1);

+printf("\t delt2 is : %.0f F \n",delt2);

+LMTDc=((delt2-delt1)/((2.3)*(log10(delt2/delt1))));

+printf("\t LMTD is :%.1f F \n",LMTDc);

+w1=(qc/LMTDc);

+printf("\t w1 is : %.2e lb/hr \n",w1);

+printf("\t subcooling \n");

+delt3=T3-t1; //F

+delt4=T2-t2; // F

+printf("\t delt1 is : %.0f F \n",delt3);

+printf("\t delt2 is : %.0f F \n",delt4);

+LMTDs=((delt4-delt3)/((2.3)*(log10(delt4/delt3))));

+printf("\t LMTD is :%.1f F \n",LMTDs);

+w2=(qs/LMTDs);

+printf("\t w1 is : %.2e lb/hr \n",w2);

+delt=(Q/(w1+w2));

+printf("\t delt is : % .1f F \n",delt);

+Tc=((T1)+(T2))/(2); // caloric temperature of hot fluid,F

+printf("\t caloric temperature of hot fluid is : %.1f F \n",Tc);

+tc=((t1)+(t3))/(2); // caloric temperature of cold fluid,F

+printf("\t caloric temperature of cold fluid is : %.0f F \n",tc);

+printf("\t hot fluid:shell side,pentane \n");

+C1=0.198; // for 0.3Ds

+Ds=25; // in

+L=16; // ft

+N=370

+a=(C1*Ds^2);

+printf("\t a is : %.0f in^2 \n",a);

+N1=((N*a*4)/(3.14*Ds^2));

+printf("\t number of submerged tubes are : %.0f \n",N1);

+Nt=N-N1;

+printf("\t number of tubes for condensation are : %.0f \n",Nt);

+Af=(N1/N);

+printf("\t flooded surface : %.2f \n",Af);

+printf("\t for condensaton \n");

+G1=(W/(L*Nt^(2/3))); // from eq.12.43

+printf("\t G1 is : %.1f lb/(hr)*(lin ft) \n",G1);

+printf("\t cold fluid:inner tube side,water \n");

+n=4; // number of passes

+L=16; //ft

+at1=0.302; // flow area, in^2

+at=((Nt*at1)/(144*n)); // total area,ft^2,from eq.7.48

+printf("\t flow area is : %.3f ft^2 \n",at);

+Gt=(w/(at)); // mass velocity,lb/(hr)*(ft^2)

+printf("\t mass velocity is : %.1e lb/(hr)*(ft^2) \n",Gt);

+V=(Gt/(3600*62.5));

+printf("\t V is : %.2f fps \n",V);

+mu2=1.98; // lb/(ft)*(hr)

+D=0.0517; // ft

+Ret=((D)*(Gt)/mu2); // reynolds number

+printf("\t reynolds number is : %.2e \n",Ret);

+hi=940; //Btu/(hr)*(ft^2)*(F)

+printf("\t hi is : %.0f Btu/(hr)*(ft^2)*(F) \n",hi);

+ID=0.62; // ft

+OD=0.75; //ft

+hio=((hi)*(ID/OD)); // using eq.6.5

+printf("\t Correct hio to the surface at the OD is : %.0f Btu/(hr)*(ft^2)*(F) \n",hio);

+ho=251; // Btu/(hr)*(ft^2)*(F), from fig 12.9

+printf("\t Correct ho to the surface at the OD is : %.0f Btu/(hr)*(ft^2)*(F) \n",ho);

+Uc=((hio)*(ho)/(hio+ho)); // clean overall coefficient,Btu/(hr)*(ft^2)*(F)

+printf("\t clean overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",Uc);

+Ac=(qc/(Uc*LMTDc));

+printf("\t clean surface required for dcondensation : %.0f ft^2 \n",Ac);

+printf("\t subcooling \n");

+ho=50; // Btu/(hr)*(ft^2)*(F)

+printf("\t individual heat transfer coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",ho);

+Us=((hio)*(ho)/(hio+ho)); // clean overall coefficient,Btu/(hr)*(ft^2)*(F)

+printf("\t clean overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",Us);

+As=(qs/(Us*LMTDs));

+printf("\t clean surface required for desuperheating : %.0f ft^2 \n",As);

+AC=As+Ac;

+printf("\t total clean surface : %.0f ft^2 \n",AC);

+UC=((Us*As)+(Uc*Ac))/(AC);

+printf("\t weighted clean overall coefficient : %.0f Btu/(hr)*(ft^2)*(F) \n",UC);

+A=1160; // ft^2

+printf("\t total surface area is : %.0f ft^2 \n",A);

+UD=((Q)/((A)*(delt)));

+printf("\t actual design overall coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",UD);

+Rd=((UC-UD)/((UD)*(UC))); // (hr)*(ft^2)*(F)/Btu

+printf("\t actual Rd is : %.4f (hr)*(ft^2)*(F)/Btu \n",Rd);

+printf("\t pressure drop  for annulus \n");

+printf("\t condensation \n");

+printf("\t It will be necessary to spread the batHes to a spacing of 18in.to compensate for the reduction in crossfiow area due to the flooded subcooling zone. The tube-side pressure drop will be the same as before. Assume bundle flooded to 0.3Ds.\n");

+As=0.547; // ft^2

+Gs=(W/(As)); // mass velocity,lb/(hr)*(ft^2)

+printf("\t mass velocity is : %.1e lb/(hr)*(ft^2) \n",Gs);

+De=0.0792; // fig 28

+Res=((De)*(Gs)/0.0165); // reynolds number

+printf("\t reynolds number is : %.2e \n",Res);

+f=0.00121; // friction factor for reynolds number 193000, using fig.29

+s=0.00454; // for reynolds number 193000,using fig.6

+Ds=2.08; // ft

+B=18

+phys=1;

+N=(12*L/B); // number of crosses,using eq.7.43

+printf("\t number of crosses are : %.0f \n",N);

+delPsc=((f*(Gs^2)*(Ds)*(N))/(5.22*(10^10)*(De)*(s)*(phys)))/(2); // using eq.12.47,psi

+printf("\t delPsc is : %.1f psi \n",delPsc);

+printf("\t delPss is negligible \n");

+printf("\t allowable delPa is 2 psi \n");

+//end