initial commit / add all books

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diff --git a/1328/CH12/EX12.3/12_3.sce b/1328/CH12/EX12.3/12_3.sce
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+printf("\t example 12.3 \n");

+printf("\t approximate values are mentioned in the book \n");

+T1=200; // inlet hot fluid,F

+T2=130; // outlet hot fluid,F

+T3=125; // after condensation

+t1=65; // inlet cold fluid,F

+t3=100; // outlet cold fluid,F

+W=27958; // lb/hr

+w=135500; // lb/hr

+printf("\t 1.for heat balance \n");

+printf("\t for butane \n");

+c=0.44; // Btu/(lb)(F)

+qd=((W)*(c)*(T1-T2)); // Btu/hr

+printf("\t total heat required for desuperheating of butane is : %.1e Btu/hr \n",qd);

+HT2=309; // enthalpy at T2, Btu/lb

+HT3=170; // enthalpy at T3, Btu/lb

+qc=(W*(HT2-HT3)); // for condensation

+printf("\t total heat required for condensing of butane is : %.2e Btu/hr \n",qc);

+Q=qd+qc;

+printf("\t total heat required for  butane is : %.2e Btu/hr \n",Q);

+printf("\t for water \n");

+c=1; // Btu/(lb)*(F)

+Q=((w)*(c)*(t3-t1)); // Btu/hr

+printf("\t total heat required for water is : %.2e Btu/hr \n",Q);

+deltw=(qc/w);

+printf("\t deltw is : %.1f F \n",deltw);

+t2=t1+deltw;

+printf("\t t2 is : %.1f F \n",t2)

+printf("\t for desuperheating \n");

+delt1=T2-t2; //F

+delt2=T1-t3; // F

+printf("\t delt1 is : %.0f F \n",delt1);

+printf("\t delt2 is : %.0f F \n",delt2);

+LMTDd=((delt2-delt1)/((2.3)*(log10(delt2/delt1))));

+printf("\t LMTD is :%.0f F \n",LMTDd);

+w1=(qd/LMTDd);

+printf("\t w1 is : %.3e lb/hr \n",w1);

+printf("\t for condensing \n");

+delt3=T3-t1; //F

+delt4=T2-t2; // F

+printf("\t delt1 is : %.0f F \n",delt3);

+printf("\t delt2 is : %.0f F \n",delt4);

+LMTDc=((delt4-delt3)/((2.3)*(log10(delt4/delt3))));

+printf("\t LMTD is :%.0f F \n",LMTDc);

+w2=(qc/LMTDc);

+printf("\t w1 is : %.2e lb/hr \n",w2);

+delt=(Q/(w1+w2));

+printf("\t delt is : % .1f F \n",delt);

+Tc=((T3)+(T2))/(2); // caloric temperature of hot fluid,F

+printf("\t caloric temperature of hot fluid is : %.1f F \n",Tc);

+tc=((t1)+(t3))/(2); // caloric temperature of cold fluid,F

+printf("\t caloric temperature of cold fluid is : %.1f F \n",tc);

+printf("\t hot fluid:shell side,butane \n");

+ID=23.25; // in

+C=0.25; // clearance

+B=12; // baffle spacing,in

+PT=1;

+as=((ID*C*B)/(144*PT)); // flow area,ft^2

+printf("\t flow area is : %.3f ft^2 \n",as);

+printf("\t desuperheating \n");

+Gs=(W/as); // mass velocity,lb/(hr)*(ft^2)

+printf("\t mass velocity is : %.2e lb/(hr)*(ft^2) \n",Gs);

+mu1=0.0242; // at 165F,lb/(ft)*(hr), from fig.15

+De=0.73/12; // from fig.28,ft

+Res=((De)*(Gs)/mu1); // reynolds number

+printf("\t reynolds number is : %.2e \n",Res);

+jH=239; // from fig.28

+k=0.012; // Btu/(hr)*(ft^2)*(F/ft), from table 5

+Z=0.96; // Z=((c)*(mu1)/k)^(1/3)

+ho=((jH)*(k/De)*(Z)); // H0=(h0/phya),using eq.6.15b,Btu/(hr)*(ft^2)*(F)

+printf("\t individual heat transfer coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",ho);

+printf("\t cold fluid:inner tube side,water \n");

+Nt=352;

+n=4; // number of passes

+L=16; //ft

+at1=0.302; // flow area,table 10, in^2

+at=((Nt*at1)/(144*n)); // total area,ft^2,from eq.7.48

+printf("\t flow area is : %.3f ft^2 \n",at);

+Gt=(w/(at)); // mass velocity,lb/(hr)*(ft^2)

+printf("\t mass velocity is : %.2e lb/(hr)*(ft^2) \n",Gt);

+V=(Gt/(3600*62.5));

+printf("\t V is : %.2f fps \n",V);

+mu2=2.11; // at 82.5F, fig 14,lb/(ft)*(hr)

+D=0.0517; // ft

+Ret=((D)*(Gt)/mu2); // reynolds number

+printf("\t reynolds number is : %.2e \n",Ret);

+hi=800; // fig 25,Btu/(hr)*(ft^2)*(F)

+printf("\t hi is : %.0f Btu/(hr)*(ft^2)*(F) \n",hi);

+ID=0.62; // ft

+OD=0.75; //ft

+hio=((hi)*(ID/OD)); // using eq.6.5

+printf("\t Correct hio to the surface at the OD is : %.0f Btu/(hr)*(ft^2)*(F) \n",hio);

+Ud=((hio)*(ho)/(hio+ho)); // clean overall coefficient,eq 6.38,Btu/(hr)*(ft^2)*(F)

+printf("\t clean overall coefficient is : %.1f Btu/(hr)*(ft^2)*(F) \n",Ud);

+Ad=(qd/(Ud*LMTDd));

+printf("\t clean surface required for desuperheating : %.0f ft^2 \n",Ad);

+printf("\t for condensaton \n");

+Lc=16*0.6; // condensation occurs 60% of the tube length

+G1=(W/(Lc*Nt^(2/3))); // from eq.12.43

+printf("\t G1 is : %.1f lb/(hr)*(lin ft) \n",G1);

+ho=200; // assumption

+tw=(tc)+(((ho)/(hio+ho))*(Tc-tc)); // from eq.5.31

+printf("\t tw is : %.0f F \n",tw);

+tf=(Tc+tw)/(2); // from eq 12.19

+printf("\t tf is : %.0f F \n",tf);

+kf=0.075; // Btu/(hr)*(ft^2)*(F/ft)

+sf=0.55; // from table 6

+muf=0.14; // cp, from fig 14

+ho=207; // Btu/(hr)*(ft^2)*(F), from fig 12.9

+printf("\t Correct ho to the surface at the OD is : %.0f Btu/(hr)*(ft^2)*(F) \n",ho);

+Uc=((hio)*(ho)/(hio+ho)); // clean overall coefficient,Btu/(hr)*(ft^2)*(F)

+printf("\t clean overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",Uc);

+Ac=(qc/(Uc*LMTDc));

+printf("\t clean surface required for desuperheating : %.0f ft^2 \n",Ac);

+AC=Ad+Ac;

+printf("\t total clean surface : %.0f ft^2 \n",AC);

+lc=(Ac/(Ac+Ad));

+printf("\t assumed condensing length percentage : %.2f \n",lc);

+UC=((Ud*Ad)+(Uc*Ac))/(AC);

+printf("\t weighted clean overall coefficient : %.0f Btu/(hr)*(ft^2)*(F) \n",UC);

+A2=0.1963; // actual surface supplied for each tube,ft^2,from table 10

+A=(Nt*L*A2); // ft^2

+printf("\t total surface area is : %.0f ft^2 \n",A);

+UD=((Q)/((A)*(delt)));

+printf("\t actual design overall coefficient is : %.0f Btu/(hr)*(ft^2)*(F) \n",UD);

+Rd=((UC-UD)/((UD)*(UC))); // (hr)*(ft^2)*(F)/Btu

+printf("\t actual Rd is : %.4f (hr)*(ft^2)*(F)/Btu \n",Rd);

+printf("\t pressure drop  for annulus \n");

+printf("\t desuperheating \n");

+Ld=6.4; //ft

+De=0.0608; // fig 28

+f=0.0013; // friction factor for reynolds number 145000, using fig.29

+Ds=1.94; // ft

+phys=1;

+N=(12*Ld/B); // number of crosses,using eq.7.43

+printf("\t number of crosses are : %.0f \n",N);

+row=(58.1/((359)*(625/492)*(14.7/99.7)));

+printf("\t row is %.3f lb/ft^3 \n",row);

+s=(row/62.5);

+printf("\t s is %.4f \n",s);

+delPsd=((f*(Gs^2)*(Ds)*(N))/(5.22*(10^10)*(De)*(s)*(phys))); // using eq.7.44,psi

+printf("\t delPs is : %.1f psi \n",delPsd);

+printf("\t condensation \n");

+N=(12*Lc/B); // number of crosses,using eq.7.43

+printf("\t number of crosses are : %.0f \n",N);

+delPsc=((f*(Gs^2)*(Ds)*(N))/(5.22*(10^10)*(De)*(s)*(phys)))/(2); // using eq 12.47,psi

+printf("\t delPsc is : %.1f psi \n",delPsc);

+delPS=delPsd+delPsc;

+printf("\t delPS is : %.0f psi \n",delPS);

+printf("\t allowable delPa is 2 psi \n");

+printf("\t pressure drop  for inner pipe \n");

+f=0.00023; // friction factor for reynolds number 17900, using fig.26

+s=1;

+phyt=1;

+delPt=((f*(Gt^2)*(L)*(n))/(5.22*(10^10)*(D)*(s)*(phyt))); // using eq.7.45,psi

+printf("\t delPt is : %.0f psi \n",delPt);

+X1=0.075; // X1=((V^2)/(2*g)),using fig.27

+delPr=((4*n*X1)/(s)); // using eq.7.46,psi

+printf("\t delPr is : %.1f psi \n",delPr);

+delPT=delPt+delPr; // using eq.7.47,psi

+printf("\t delPT is : %.1f psi \n",delPT);

+printf("\t allowable delPa is 10 psi \n");

+//end