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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//to find the equivalent dynamical system
+//gravitaional force (g)=32.2 ft/s^2
+clc
+printf("\n")
+//given
+m=2.5//lb
+a=6//in
+k=3.8//in
+l=9//in
+c=3//in
+w=22500
+//k^2=ab
+//case a) to find equivalent dynamic system
+b=(k^2)/a
+ma=(2.5*6)/8.42//m*a/a+b
+mb=m-ma
+printf("Mass ma =%.2f lb will be situated at 6 inches from cg and mb =%.2f lb will be situated at %.2f inches from cg in the equivalent dynamical system",ma,mb,b)
+printf("\n")
+//if two masses are situated at the bearing centres
+ma1=(2.5*6)/9
+mb1=m-ma1
+k1=(a*c)^.5
+//t=m*((k1^2)-(k^2))*w
+t=((2.5*(18-3.8^2))*22500)/(32.2*12*12)
+printf("correction couple which must be applied in order that the two mass system is dynamically equivalent to the rod is given by %.2f lb ft\n",t)
+