initial commit / add all books

20 files changed, 209 insertions, 0 deletions

diff --git a/1325/CH15/EX15.1/15_1.PNG b/1325/CH15/EX15.1/15_1.PNG
new file mode 100644
index 000000000..ea5469f2d
--- /dev/null
+++ b/1325/CH15/EX15.1/15_1.PNG
diff --git a/1325/CH15/EX15.1/15_1.sce b/1325/CH15/EX15.1/15_1.sce
new file mode 100644
index 000000000..e983bc7c9
--- /dev/null
+++ b/1325/CH15/EX15.1/15_1.sce
@@ -0,0 +1,21 @@
+//to find the frequencies of the free longitudinal, transverse and torsional vibrations

+clc

+//given

+W=.3*2240//lb

+l=36//in

+D=3//in

+k=15//in

+A=%pi*(D/2)^2

+E=30*10^6//youngs modulus

+C=12*10^6

+g=32.2//ft/s^2

+d=W*l/(A*E)

+Fl=187.8/(d)^(1/2)

+I=%pi*(d/2)^4

+d1=W*(l^3)*64/(3*E*%pi*(3^4))

+Ft=187.8/(d1)^(1/2)

+j=%pi*3^4/32

+q=C*j/l

+Ftor=(1/(2*%pi))*(q*g*12/(W*k^2))^(1/2)

+F1=Ftor*60

+printf("\na) Frequency of Longitudinal vibrations = %.f per min\nb) Frequency of the transverse vibrations = %.f per min\nc) Frequency of the torsional vibration = %.f per min",Fl,Ft,F1)

diff --git a/1325/CH15/EX15.11/15_11.PNG b/1325/CH15/EX15.11/15_11.PNG
new file mode 100644
index 000000000..4a94d2d2c
--- /dev/null
+++ b/1325/CH15/EX15.11/15_11.PNG
diff --git a/1325/CH15/EX15.11/15_11.sce b/1325/CH15/EX15.11/15_11.sce
new file mode 100644
index 000000000..9be8a056d
--- /dev/null
+++ b/1325/CH15/EX15.11/15_11.sce
@@ -0,0 +1,28 @@
+//to find the natural frequencies of the torsional vibration of the system when inertia is neglected and when it is taken into account

+clc

+//given

+g=32.3//ft/s^2

+l2=25.5//in

+d1=2.75//in

+d2=3.5//in

+C=12*10^6//modulus of rigidity

+G=1/0.6//given speed ratio

+Ib=54//lb in^2

+Ic=850//lb in^2

+Id=50000//lb in^2

+Id1=Id/G^2//15.62

+Ia=1500//lb in^2

+la=Id1/(Id1+Ia)*66.5

+J=%pi*d1^4/32

+q=C*J/la//torsional stiffness

+n=(1/(2*%pi))*(q*g*12/Ia)^(1/2)

+nf=n*60//for minutes

+//case b)

+Ib1=Ib+Ic/(G^2)

+a=63.15//in; distance of the node from rotor A (given)

+b=3.661//in; distance of the node from rotor A (given)

+N1=n*(la/a)^(1/2)

+N2=n*(la/b)^(1/2)

+N1f=N1*60//for minutes

+N2f=N2*60//for minutes

+printf("\na) The frequency of torsional vibrations n = %.1f per sec or %.f per min\nb) The fundamental frquency = %.1f per sec or %.f per min\n   and the two node frequency = %.f per sec or %.f per min",n,nf,N1,N1f,N2,N2f)

diff --git a/1325/CH15/EX15.2/15_2.PNG b/1325/CH15/EX15.2/15_2.PNG
new file mode 100644
index 000000000..1913f0ec1
--- /dev/null
+++ b/1325/CH15/EX15.2/15_2.PNG
diff --git a/1325/CH15/EX15.2/15_2.sce b/1325/CH15/EX15.2/15_2.sce
new file mode 100644
index 000000000..dc8e933c9
--- /dev/null
+++ b/1325/CH15/EX15.2/15_2.sce
@@ -0,0 +1,24 @@
+//To find the natural frequencies of the longitudinal, transverse and torsional vibration of the system

+clc

+//given

+l1=3//ft

+l2=2//ft

+l=l1+l2//ft

+W=.5*2240//lb

+k=20//in

+d=2//in

+Wa=2*W/5

+E=30*10^6

+A=%pi*(d/2)^2

+d1=Wa*l1*12/(A*E)

+N1=187.8/(d1)^(1/2)

+I=%pi*(d)^4/64

+d2=W*(l1*12)^3*(l2*12)^3/(3*E*(l*12)^3*I)

+N2=187.8/(d2)^(1/2)

+C=12*10^6//given

+g=32.2//given

+J=%pi*d^4/32

+q=C*J*((1/(l1*12))+(1/(l2*12)))

+n=(1/(2*%pi))*(q*g*12/(W*k^2))^(1/2)

+N3=n*60

+printf("\na)Longitudinal vibration = %.f per min\nb)Transverse Vibration = %.f per min\nc)Torsional Vibration = %.f per min\n",N1,N2,N3)

diff --git a/1325/CH15/EX15.3/15_3.PNG b/1325/CH15/EX15.3/15_3.PNG
new file mode 100644
index 000000000..5ab75a7c1
--- /dev/null
+++ b/1325/CH15/EX15.3/15_3.PNG
diff --git a/1325/CH15/EX15.3/15_3.sce b/1325/CH15/EX15.3/15_3.sce
new file mode 100644
index 000000000..03cf93309
--- /dev/null
+++ b/1325/CH15/EX15.3/15_3.sce
@@ -0,0 +1,10 @@
+//to find frequency of the natural transverse vibration

+clc

+//given

+l=10//ft

+d=4//in

+E=30*10^6//youngs modulus

+d1=0.0882//inches; maximum deflection as shown in the figure

+N=207/(d1)^(1/2)//From 15.20

+printf("\nFrequency of natural transverse vibration = %.f per min",N)

+

diff --git a/1325/CH15/EX15.4/15_4.PNG b/1325/CH15/EX15.4/15_4.PNG
new file mode 100644
index 000000000..b204f02c5
--- /dev/null
+++ b/1325/CH15/EX15.4/15_4.PNG
diff --git a/1325/CH15/EX15.4/15_4.sce b/1325/CH15/EX15.4/15_4.sce
new file mode 100644
index 000000000..517438f67
--- /dev/null
+++ b/1325/CH15/EX15.4/15_4.sce
@@ -0,0 +1,14 @@
+//To find the resistance offered by the dashpot

+clc

+//given

+m=50//lb

+k=100//lb/in

+g=32.2//ft/s

+d=m/k//static deflection

+n=(1/(2*%pi))*(g*12/d)^(1/2)

+//part 2

+b=g*12/d

+a=(b/20.79)^(1/2)

+nd=(1/(2*%pi))*((b-(a/2)^2))^(1/2)

+A=nd/n

+printf("\nFrequency of free vibrations = %.3f per sec\nFrequency of damped vibrations = %.3f per sec \nThe ratio of the frequencies of damped and free vibrationsis %.3f \n",n,nd,A)

diff --git a/1325/CH15/EX15.5/15_5.PNG b/1325/CH15/EX15.5/15_5.PNG
new file mode 100644
index 000000000..78dd674bc
--- /dev/null
+++ b/1325/CH15/EX15.5/15_5.PNG
diff --git a/1325/CH15/EX15.5/15_5.sce b/1325/CH15/EX15.5/15_5.sce
new file mode 100644
index 000000000..6c525fa5b
--- /dev/null
+++ b/1325/CH15/EX15.5/15_5.sce
@@ -0,0 +1,18 @@
+//To find the ratio nd/n

+clc

+//given

+//damping torque is directly proposrtional to the angular velocity

+C=12*10^6//Modulus of rigidity

+l=3//ft

+d=1//in

+g=32.2//ft/s^2

+I=500//lb ft^2 ; moment of inertia

+J=%pi*d^4/32

+q=C*J/(l*12)

+n=(1/(2*%pi))*(q*g*12/(I*12^2))^(1/2)

+//part 2 

+b1=(q*g*12/(I*12^2))

+a1=(b1/10.15)^(1/2)//by reducing equation 15.28

+nd=(1/(2*%pi))*(b1-(a1/2)^2)^(1/2)

+A=nd/n

+printf("\nThe frequency of natural vibration = %.2f per sec\nThe frequency of damped vibration = %.2f per sec\nThe ratio nd/n = %.3f\n",n,nd,A)

diff --git a/1325/CH15/EX15.6/15_6.PNG b/1325/CH15/EX15.6/15_6.PNG
new file mode 100644
index 000000000..85bdcde90
--- /dev/null
+++ b/1325/CH15/EX15.6/15_6.PNG
diff --git a/1325/CH15/EX15.6/15_6.sce b/1325/CH15/EX15.6/15_6.sce
new file mode 100644
index 000000000..4e62ef86d
--- /dev/null
+++ b/1325/CH15/EX15.6/15_6.sce
@@ -0,0 +1,18 @@
+//to  find the amplitude if the period of the applied force coincided with the natural period of vibration of the system

+clc

+//given

+m=20//lb

+k=50//lb/in

+F=30//lb

+w=50//sec^-1 

+g=32.2//ft/s^2

+d=m/k

+x=F/k//extension of the spring

+b=g*12/d

+a=(b/30.02)^(1/2)//from equation 15.28

+D=1/((1-w^2/b)^2+a^2*w^2/b^2)^(1/2)

+Af=D*x//amplitude of forced vibration 

+D=(b/a^2)^(1/2)//At resonance

+A=D*x//amplitude at resonance

+printf("\nAmplitude of forced vibrations = %.3f in\nAmplitude of the forced vibrations at resonance = %.2f in",Af,A)

+

diff --git a/1325/CH15/EX15.7/15_7.PNG b/1325/CH15/EX15.7/15_7.PNG
new file mode 100644
index 000000000..1f95a6e9b
--- /dev/null
+++ b/1325/CH15/EX15.7/15_7.PNG
diff --git a/1325/CH15/EX15.7/15_7.sce b/1325/CH15/EX15.7/15_7.sce
new file mode 100644
index 000000000..840abf0f0
--- /dev/null
+++ b/1325/CH15/EX15.7/15_7.sce
@@ -0,0 +1,27 @@
+//to find the fraction of the applied force transmitted at 1200 rpm and the amplitude of forced vibrations of the machines at resonance

+clc

+//given

+e=1/30

+n=1200//rpm

+w=%pi*n/30

+m=3//lb

+g=32.2//ft/s^2

+stroke=3.5//in

+r=stroke/2

+k=(1+1/e)^(1/2)//nf/n=k

+d=(k/187.7)^2

+W=200//lb ; given

+s=W/d//combined stiffness

+p=1/14.1//As a^2/b=1/198

+T=((1+p^2*k^2/((1-k^2)^2+p^2*k^2)))^(1/2)//actual value of transmissibility

+F=(m/g)*w^2*r/12//maximum unbalanced force transmitted on the machine

+Fmax=F*T//maximum force transmitted to the foundation

+//case b

+E=((1+p^2)/(p^2))^(1/2)

+Nreso=215.5//rpm

+Fub=F*(Nreso/n)^2

+Ftmax=E*Fub

+D=E//dynamic magnifier

+del=Fub/152//static deflection

+A=del*D

+printf("\na) Maximum force transmitted at 1200 rpm = %.f lb\nb) The amplitude of the forced vibrations of the machine at resonance = %.3f in\n   Force transmitted = %.f lb\n",Fmax,A,Fub)

diff --git a/1325/CH15/EX15.8/15_8.PNG b/1325/CH15/EX15.8/15_8.PNG
new file mode 100644
index 000000000..14a885501
--- /dev/null
+++ b/1325/CH15/EX15.8/15_8.PNG
diff --git a/1325/CH15/EX15.8/15_8.sce b/1325/CH15/EX15.8/15_8.sce
new file mode 100644
index 000000000..a7b64e5a3
--- /dev/null
+++ b/1325/CH15/EX15.8/15_8.sce
@@ -0,0 +1,24 @@
+//To find the frequency of the natural torsional oscillations of the system

+clc

+//given

+l1=11//in

+l2=10//in

+l3=15//in

+l4=4//in

+l5=10//in

+d1=3//in

+d2=5//in

+d3=3.5//in

+d4=7//in

+d5=5//in

+I1=1500//lb ft^2

+I2=1000//lb ft^2

+leq=3//in from 15.49

+g=32.2//ft/s^2

+C=12*10^6

+J=%pi*leq^4/32

+l=l1+l2*(leq/d2)^4+l3*(leq/d3)^4+l4*(leq/d4)^4+l5*(leq/d5)^4

+la=I2*l/(I1+I2)

+qa=C*J/la

+n=(1/(2*%pi))*(qa*g*12/(I1*12^2))^(1/2)

+printf("\nThe frequency of the natural torsional oscillation of the system = %.1f per sec",n)

diff --git a/1325/CH15/EX15.9/15_9.PNG b/1325/CH15/EX15.9/15_9.PNG
new file mode 100644
index 000000000..b3c67de9a
--- /dev/null
+++ b/1325/CH15/EX15.9/15_9.PNG
diff --git a/1325/CH15/EX15.9/15_9.sce b/1325/CH15/EX15.9/15_9.sce
new file mode 100644
index 000000000..84df93a92
--- /dev/null
+++ b/1325/CH15/EX15.9/15_9.sce
@@ -0,0 +1,25 @@
+//To find the  frequencies of the  free  torsional vibrations of the system

+clc

+//given

+Ia=2.5//ton ft^2

+Ib=7.5//ton ft^2

+Ic=3//ton ft^2

+g=32.2//ft/s^2

+AB=9.5//ft

+BC=25//ft

+d=8.5//in

+C=11.8*10^6//lb/in^2

+k=Ic/Ia//la/lc=k

+lc1=(25.6+(25.6^2-4*114.1)^(1/2))/2//from 1 and 2 , reducing using quadratic formula

+lc2=(25.6-(25.6^2-4*114.1)^(1/2))/2//from 1 and 2 , reducing using quadratic formula

+la1=lc1*k

+la2=lc2*k

+J=%pi*d^4/32

+q=C*J/(lc1*12)//torsional stiffness

+IC=Ic*2240*12^2/(g*12)//moment of inertia

+nc=(1/(2*%pi))*(q/IC)^(1/2)//fundamental frequency of vibration

+a1=nc*60

+a=floor(a1)

+n=16*(lc1/lc2)^(1/2)

+b=n*60

+printf("\nFundamental frequency of vibration = %.f per min\nTwo node frequency = %.f per min\n",a,b)