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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+//To find the torque exerted on AB to overcome the inertia of the links and the forces which act on the pins B and C
+clc
+//given
+AB=2.5//in
+BC=7//in
+CD=4.5//in
+AD=8//in
+ED=2.3//from figure
+N=180
+w=N*%pi/30
+m=3//lb
+k=3.5//radius of gyration
+g=32.2//ft/s^2
+QT=1.35//inches from figure
+alpha=w^2*(QT/CD)
+Torque=m*(k/12)^2*alpha/g
+Torque1=Torque*12
+Tadd=m*ED//additional torque
+Tc=Tadd+Torque1//total torque
+Fc1=Tc/CD
+//link BC
+M=5//lb
+gA=1.8//in
+fg=w^2*(gA/12)
+F=M*fg/g
+OaG=5.6//in
+Kg=2.9//in
+GZ=Kg^2/OaG
+//scaled from figure
+IB=9//in
+IC=5.8//in
+IX=2.49//in
+IY=1.93//in
+Fb1=(Fc1*IC+F*IX+M*IY)/IB
+Tor=Fb1*AB
+//from force polygon
+Fc2=1//lb
+Fb2=15.2//lb
+Fb=(Fb1^2+Fb2^2)^(1/2)
+Fc=(Fc1^2+Fc2^2)^(1/2)
+printf("\nThe torque which must be exerted on AB in order to overcome the inertia of the links = Fb1*AB = %.1f lb.in\nThe total force applied to the link BC \nAt pin C = %.2f lb\nAt pin B = %.1f lb\n",Tor,Fc,Fb)