initial commit / add all books

12 files changed, 87 insertions, 0 deletions

diff --git a/1325/CH10/EX10.1/10_1.PNG b/1325/CH10/EX10.1/10_1.PNG
new file mode 100644
index 000000000..cff240e51
--- /dev/null
+++ b/1325/CH10/EX10.1/10_1.PNG
diff --git a/1325/CH10/EX10.1/10_1.sce b/1325/CH10/EX10.1/10_1.sce
new file mode 100644
index 000000000..2afff4e9d
--- /dev/null
+++ b/1325/CH10/EX10.1/10_1.sce
@@ -0,0 +1,7 @@
+//To find pitch diameter

+clc

+//given

+Teeth=48

+pitch=.75 //in

+D=Teeth*pitch/%pi

+printf("The pitch diameter is %.3f in",D)

diff --git a/1325/CH10/EX10.2/10_2.PNG b/1325/CH10/EX10.2/10_2.PNG
new file mode 100644
index 000000000..d3c208707
--- /dev/null
+++ b/1325/CH10/EX10.2/10_2.PNG
diff --git a/1325/CH10/EX10.2/10_2.sce b/1325/CH10/EX10.2/10_2.sce
new file mode 100644
index 000000000..e639b50f2
--- /dev/null
+++ b/1325/CH10/EX10.2/10_2.sce
@@ -0,0 +1,8 @@
+//To find pitch diameter and the circular pitch

+clc

+//given

+T=48//teeth

+pd=4//diametral pitch

+D=T/pd//pitch diameter

+p=%pi/pd//the circular pitch

+printf("\nThe pitch diameter = %.f in\nThe circular pitch = %.4f in\n",D,p)

diff --git a/1325/CH10/EX10.3/10_3.PNG b/1325/CH10/EX10.3/10_3.PNG
new file mode 100644
index 000000000..937c65dcc
--- /dev/null
+++ b/1325/CH10/EX10.3/10_3.PNG
diff --git a/1325/CH10/EX10.3/10_3.sce b/1325/CH10/EX10.3/10_3.sce
new file mode 100644
index 000000000..a82ca058e
--- /dev/null
+++ b/1325/CH10/EX10.3/10_3.sce
@@ -0,0 +1,10 @@
+//Find pitch diameter and pitch module

+clc

+//given

+T=48

+m=6//mm ; module

+D=m*T

+p=%pi*m

+dia=D/10//cm

+P=p*0.0393700787//inches

+printf("\nPitch diameter = %.1f cm\nCircular pitch = %.4f in\n",dia,P)

diff --git a/1325/CH10/EX10.4/10_4.PNG b/1325/CH10/EX10.4/10_4.PNG
new file mode 100644
index 000000000..d15cb9cfa
--- /dev/null
+++ b/1325/CH10/EX10.4/10_4.PNG
diff --git a/1325/CH10/EX10.4/10_4.sce b/1325/CH10/EX10.4/10_4.sce
new file mode 100644
index 000000000..de06f8dc8
--- /dev/null
+++ b/1325/CH10/EX10.4/10_4.sce
@@ -0,0 +1,19 @@
+//To find the smallest number of teeth 

+clc

+//given

+phi=20*%pi/180

+//Solution a)

+ar=1

+t1=2*ar/sin(phi)^2//from equation 10.7

+T1=ceil(t1)

+//Solution b)

+aw=1

+t2=2*aw/((1+3*sin(phi)^2)^(1/2)-1)//from euation 10.6

+T2=ceil(t2)

+//solution c)

+t=1

+T=3

+A=(t/T)*(t/T+2)

+t3=2*aw*(t/T)/((1+A*sin(phi)^2)^(1/2)-1)//from 10.5

+T3=ceil(t3)

+printf("\nSmallest number of teeth theoretically required in order to avoid interference on a pinion which is to gear with\na) A rack , t= %.f\nb) An equal pinion , t=  %.f\nc) A wheel to give a ratio of 3 to 1 , t= %.f\n",T1,T2,T3)

diff --git a/1325/CH10/EX10.5/10_5.PNG b/1325/CH10/EX10.5/10_5.PNG
new file mode 100644
index 000000000..5de659026
--- /dev/null
+++ b/1325/CH10/EX10.5/10_5.PNG
diff --git a/1325/CH10/EX10.5/10_5.sce b/1325/CH10/EX10.5/10_5.sce
new file mode 100644
index 000000000..d427f8609
--- /dev/null
+++ b/1325/CH10/EX10.5/10_5.sce
@@ -0,0 +1,14 @@
+//To find the addendum required

+clc

+//given

+t=25

+phi=20*%pi/180

+//let pitch be 1 

+R=t/(2*%pi)//R=t*p/(2*%pi)

+Larc=1.6//1.6*p

+//AB=Larc*cos(phi)

+AB=Larc*cos(phi)

+Ra=(4.47+13.97)^(1/2)//by simplifying AB+2{(Ra^2-R^2*cos(phi)^2)-R*sin(phi)} and using p =1

+Addendum=Ra-R

+//writing p in place of p=1

+printf("\nAddendum required = %.2fp",Addendum)

diff --git a/1325/CH10/EX10.6/10_6.PNG b/1325/CH10/EX10.6/10_6.PNG
new file mode 100644
index 000000000..40f390ef7
--- /dev/null
+++ b/1325/CH10/EX10.6/10_6.PNG
diff --git a/1325/CH10/EX10.6/10_6.sce b/1325/CH10/EX10.6/10_6.sce
new file mode 100644
index 000000000..3d93319c1
--- /dev/null
+++ b/1325/CH10/EX10.6/10_6.sce
@@ -0,0 +1,29 @@
+//to find thelength of path of contact and the length of arc of contact 

+clc

+//let module be 1

+m=1

+t1=28

+t2=45

+r=t1*m/2

+R=t2*m/2

+ra=r+m

+Ra=R+m

+phi1=14.5*%pi/180

+//10.8 => AB =(ra^2-r^2*cos(phi)^2)^(1/2)+(Ra^2-R^2*cos(phi)^2)^(1/2)-(r+R)*sin(phi)

+//AB=A+B-C

+A=m*(ra^2-r^2*cos(phi1)^2)^(1/2)

+B=m*(Ra^2-R^2*cos(phi1)^2)^(1/2)

+C=m*(r+R)*sin(phi1)

+AB=A+B-C

+p=%pi*m

+ABp=AB/%pi

+arc1=ABp/cos(phi1)//length of arc of contact

+phi2=20*%pi/180

+//10.8 => AB =(ra^2-r^2*cos(phi)^2)^(1/2)+(Ra^2-R^2*cos(phi)^2)^(1/2)-(r+R)*sin(phi)

+a=m*(ra^2-r^2*cos(phi2)^2)^(1/2)

+b=m*(Ra^2-R^2*cos(phi2)^2)^(1/2)

+c=m*(r+R)*sin(phi2)

+ab=a+b-c

+abp=ab/%pi

+arc2=abp/cos(phi2)//length of arc of contact

+printf("\nLength of path of contact\nWhen phi = 14.5 degrees = %.3fm\nWhen phi = 20 degrees = %.2fm\nLength of arc of contact\nWhen phi = 14.5 degrees = %.2fp\nWhen phi = 20 degrees = %.3fp\n",AB,ab,arc1,arc2)