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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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treeab291cffc65280e58ac82470ba63fbcca7805165 /1322/CH14/EX14.13
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+
+//6*x^2+17*x-3
+clear;
+clc;
+close;
+x=poly(0,'x');
+p=6*x^2+17*x-3;
+factors(p);
+ans(2)=ans(2)*6;//multiply by 6 the p1 factors to get the original factors of p
+disp(ans(1),ans(2),"the factors of 6*x^2+17*x-3 are")