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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Swinburne test on a dc shunt motor
+
+clc;
+clear;
+
+V=500;
+I=5;
+Rf=250;
+Ra=0.5;
+
+P=V*I;
+If=V/Rf;
+
+Ia=I-If;
+
+Pfc=(If^2)*Rf;// Field Copper Loss
+
+Pac=(Ia^2)*Ra; // Armature Copper Loss
+
+Pil=P-Pfc-Pac;// Iron loss
+
+// Generator
+
+Vg=500;
+Ig=100;
+
+Pog=Vg*Ig; // Power Output
+
+Iag=Ig+If; //Armature current
+
+Pgac=(Iag^2)*Ra; // Armature Copper loss
+
+slg=0.01*Pog;//stray loss
+
+Pgtl=Pgac+Pfc+slg+Pil; // Total losses
+
+effg=Pog*100/(Pog+Pgtl);
+
+// Motor
+
+Vm=500;
+Im=100;
+
+Pim=Vm*Im; // Power input to the motor
+
+Iam=Ig-If; // Armature current
+
+Pmac=(Iam^2)*Ra; // Armature Copper Loss
+
+Pom=Pim-Pmac-Pil-Pfc;// Ouput of the motor
+slm=0.01*Pom;// Stray loss
+
+Pmtl=Pmac+Pil+Pfc+slm; // Total loss of the motor
+
+effm=(Pom-slm)*100/(Pim);
+
+
+printf('i) The Efficiency of the machine as a generator delivering 100A at 500V = %g percent \n',effg)
+
+printf('ii) The Efficiency of the machine as a motor having a line current 100A at 500V = %g percent \n',effm)
+
+
+
+