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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Computation of Mutual and self inducatances
+
+clc;
+clear;
+
+n1=600;
+i1=2.5;
+flux1=0.4*(10^-3);
+flux2=0.8*(10^-3);
+n2=2000;
+tflux=flux1+flux2;
+
+L1=n1*tflux/i1;
+
+K=flux2/tflux;
+
+M=n2*flux2/i1;
+
+L2=((M/K)^2)/L1;
+
+disp('H',L1,'The self inductance of coil 1= ')
+disp('H',L2,'The self inductance of coil 2= ')
+
+disp('(Note the accuracy of the answer.)')
+disp('H',M,'The Mutual inductance of both coils= ')
+disp(K,'The coupling co-efficient')