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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1319/CH10/EX10.1 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '1319/CH10/EX10.1')
| -rw-r--r-- | 1319/CH10/EX10.1/10_1.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/1319/CH10/EX10.1/10_1.sce b/1319/CH10/EX10.1/10_1.sce new file mode 100644 index 000000000..724b42d54 --- /dev/null +++ b/1319/CH10/EX10.1/10_1.sce @@ -0,0 +1,14 @@ +//Determine the additional load which can be supplied
+
+clc;
+clear;
+
+printf('a) D.C two wire: \nPower transmitted by DC two wire = P and Voltage between the wires = V\n')
+printf('Copper Loss = 2 *(P/V)^2)*R ; where R is the resistance of each wire\n')
+printf('Per Unit Loss = 2*P*R/(V^2)\n\n')
+printf('b) 3 phase 3 wire: \nPower transmitted = P''\n ')
+printf('I'' = P''/(sqrt(3)*V) for unity p.f\n')
+printf('Copper Loss = 3*((P''/(sqrt(3)*V))^2)*R = ((P/V)^2)*R\n')
+printf('Per Unit Loss = P''*R/(V^2)\n\n')
+printf('Equating the per unit loss we have\n')
+printf('2*P*R/(V^2) = P''*R/(V^2) or P'' = 2P\n Which proves that 100 %% aditional pwer can be supplied by 3 phase 3 wire system\n')
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