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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//To determine the coil parameters with resistance of 5 ohms
+
+clc;
+clear;
+//Parameters of the coil
+R=5; // Resistance
+I=10; // Current flowing
+V=200;// Voltage across
+f=50;// Frequency of operation
+P=750;//Total Power Dissipated
+
+Pc=(I^2)*R; // Copper Loss
+Pil=P-Pc;// Iron Loss
+
+Z=V/I;// Impedance
+
+X=sqrt((Z^2)-(R^2));//Reactance
+
+L=X/(2*%pi*f);// Inductance
+
+pf=P/(V*I); // Power Factor
+
+printf('i The iron loss = %g W\n',Pil)
+printf('ii) The inductance at the given value of current = %g H\n',L)
+printf('iii) p.f = %g\n',pf)