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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Chapter 2
+//Example 2.10
+//Page 68
+
+clear;
+clc;
+
+R1 = 1000;
+R2 = 2000;
+R3 = 1000;
+C1 = 1;
+
+printf("Because the bridge is at null , we have \n ")
+printf("Z2*Z3 = Z1*Zx \n")
+printf("R2(R3-j/wC)=R1(Rx-j/wCx) \n")
+printf("The real and imaginary parts must be indpendently equal,so that \n")
+printf("Rx-(R2*R3/R1)=0 \n")
+//Calculation of value of Rx
+x=(R2*R3/R1)/1000
+printf("Rx = %.0f kilo ohm \n",x)
+//Calculation of value of Cx
+y=(C1*(R1/R2))
+printf("Cx=C(R1/R2) \n Cx = %.1f uF",y)
+
+