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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+//initialisation
+n=5
+h=2
+p=1/6
+//CALCULATIONS
+t=1-p
+a=((factorial(n))/(factorial(h)*factorial(n-h)))*(p^h)*(t^(n-h))
+//results
+printf(' \n probability of apperance of 4 in two dices= % 1f ',a)