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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+// Given that
+mu_0 = 1 // refractive index of air
+mu1 = 1.5 // refractive index for core
+mu2 = 1.48 // refractive index for cladding
+// Sample Problem 3 on page no. 5.16
+printf("\n # PROBLEM 3 # \n")
+theta_c = asin(mu2 / mu1) * (180 / %pi)
+delta_mu = (mu1 - mu2) / mu1
+NA = sqrt(mu1^2 - mu2^2)
+theta_0 = asin(NA) * (180 / %pi)
+printf("\n Standard formula used \n theta_c = asin(mu2 / mu1) * (180 / pi). \n delta_mu = (mu1 - mu2) / mu1. \n NA = sqrt(mu1^2 - mu2^2). \n theta_0 = asin(NA) * (180 / pi). \n ")
+printf("\n Critical angle = %f degree. \n Numerical aperture = %f. \n Acceptance angle = %f degree.\n Fractional refractive index = %f.",theta_c,NA,theta_0,delta_mu)