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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+// Given that
+mu1 = 1.6 // refractive index for core
+mu2 = 1.5 // refractive index for cladding
+// Sample Problem 2 on page no. 5.16
+printf("\n # PROBLEM 2 # \n")
+NA = sqrt(mu1^2 - mu2^2)//calculation for numerical aperture
+theta_0 = asin(NA) * (180 / %pi)//calculation for maximum incidence angle
+printf("Standard formula used \n NA=aqrt(mu1^2-mu2^2),\n sin(theta_)=NA. \n")
+printf("\n Numerical aperture = %f.\n Maximum incidence angle = %f degree.",NA,theta_0)