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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1271/CH3/EX3.6 | |
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initial commit / add all books
Diffstat (limited to '1271/CH3/EX3.6')
-rwxr-xr-x | 1271/CH3/EX3.6/6.txt | 2 | ||||
-rwxr-xr-x | 1271/CH3/EX3.6/example3_6.sce | 9 |
2 files changed, 11 insertions, 0 deletions
diff --git a/1271/CH3/EX3.6/6.txt b/1271/CH3/EX3.6/6.txt new file mode 100755 index 000000000..a8a74c30a --- /dev/null +++ b/1271/CH3/EX3.6/6.txt @@ -0,0 +1,2 @@ + Angle of incidence = 59.999272 degree
+ Angle of refraction = 30.000728 degree
diff --git a/1271/CH3/EX3.6/example3_6.sce b/1271/CH3/EX3.6/example3_6.sce new file mode 100755 index 000000000..337c39d9f --- /dev/null +++ b/1271/CH3/EX3.6/example3_6.sce @@ -0,0 +1,9 @@ +clc +// Given that +mu = 1.732 // refractive index of glass +// Sample Problem 6 on page no. 3.25 +printf("\n # PROBLEM 6 # \n") +Ip = atan(mu) * (180 / %pi) // by Brewster's law +r = 90 - Ip// calculation for angle of refraction +printf("Standard formula used \n mu=tan(Ip)\n") +printf("\n Angle of incidence = %f degree\n Angle of refraction = %f degree",Ip,r) |