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| author | priyanka | 2015-06-24 15:03:17 +0530 |
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| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1271/CH20/EX20.11/example20_11.sce | |
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initial commit / add all books
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| -rwxr-xr-x | 1271/CH20/EX20.11/example20_11.sce | 15 |
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diff --git a/1271/CH20/EX20.11/example20_11.sce b/1271/CH20/EX20.11/example20_11.sce new file mode 100755 index 000000000..a7aa242a8 --- /dev/null +++ b/1271/CH20/EX20.11/example20_11.sce @@ -0,0 +1,15 @@ +clc +// Given that +V1 = 44e3 // voltage in first case in V +V2 = 50e3 // voltage in second case in V +lambda1 = 0.284e-10 // shortest wavelength in first case in m +lambda2 = 0.248e-10 // shortest wavelength in second case in m +e = 1.6e-19 // charge on an electron in C +c = 3e8 // speed of light in m/sec +// Sample Problem 11 on page no. 20.10 +printf("\n # PROBLEM 11 # \n") +printf("Standard formula used \n ") +printf(" h*c/Lambda = eV \n") +h1 = e * V1 * lambda1 / c +h2 = e * V2 * lambda2 / c +printf("\n Planck constant is %e J sec if shortest wavelength is %e m .\n Planck constant is %e Jsec if shortest wavelength is %e m. ",h1,lambda1,h2,lambda2) |