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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1271/CH2/EX2.8/example2_8.sce | |
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initial commit / add all books
Diffstat (limited to '1271/CH2/EX2.8/example2_8.sce')
-rwxr-xr-x | 1271/CH2/EX2.8/example2_8.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/1271/CH2/EX2.8/example2_8.sce b/1271/CH2/EX2.8/example2_8.sce new file mode 100755 index 000000000..9af0ace91 --- /dev/null +++ b/1271/CH2/EX2.8/example2_8.sce @@ -0,0 +1,14 @@ +clc +// Given that +lambda = 5.89e-7 // wavelength of light in meter +d1 = 1 // distance of wavefront recieved on the screen from the opening in first side in meter +d2 = 2 // distance of wavefront recieved on the screen from the opening in other side in meter +// Sample Problem 8 on page no. 2.40 +printf("\n # PROBLEM 8 # \n") +f = (d1 * d2) / (d1 + d2) +p = 1 / f // beacause zone plate act as a convex lens +n = 1 // for first zone +Rn = sqrt(n * lambda * f) // calculation for radius of first zone +Dn = 2 * Rn // calculation for diameter of first zone +printf("\n Standard formula used \n ") +printf("\n Focal length = %f meter. \n Power = %f D. \n Diameter of first zone = %f mm. ",f,p,Dn*1000) |