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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1271/CH2/EX2.3/example2_3.sce | |
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-rwxr-xr-x | 1271/CH2/EX2.3/example2_3.sce | 10 |
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diff --git a/1271/CH2/EX2.3/example2_3.sce b/1271/CH2/EX2.3/example2_3.sce new file mode 100755 index 000000000..2588c02ba --- /dev/null +++ b/1271/CH2/EX2.3/example2_3.sce @@ -0,0 +1,10 @@ +clc +// Given that +lambda = 5e-7 // wavelength of light in meter +d = 0.3 // distance of wavefront received on screen from the opening in meter +// Sample Problem 3 on page no. 2.38 +printf("\n # PROBLEM 3 # \n") +n = 1 // no. of half period zone +Rn = sqrt(n * lambda * d) // because at maxima intensity is four time the individual intensity of light +printf("Standard formula used \n r = sqrt(d*lambda)\n") +printf("\n Radius of 80th half period zone = %f mm. ",Rn*1000) |