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authorpriyanka2015-06-24 15:03:17 +0530
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+ # PROBLEM 17 #
+ Standard formula used
+ E = (h * c)/lambda = 1/2*m*v^2
+
+ Energy of incident photon is 8.275000 eV,which is greater than the work function
+ So it causes photoelectric emission.
+ Kinetic energy of the emitted electron is 3.745000 eV.
diff --git a/1271/CH14/EX14.17/example14_17.sce b/1271/CH14/EX14.17/example14_17.sce
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+clc
+// Given that
+lambda = 1.5e-7 // wavelength of light in in meter
+w = 4.53 // work function of tungsten in eV
+h = 6.62e-34 // Planck constant in J-sec
+c = 3e8 // speed of light in m/sec
+e = 1.6e-19 // charge on an electron in C
+// Sample Problem 17 on page no. 14.26
+printf("\n # PROBLEM 17 # \n")
+printf(" Standard formula used \n ")
+printf(" E = (h * c)/lambda = 1/2*m*v^2 \n ")
+E = ((h * c) / lambda) * (1 / e)
+k = E - w
+printf("\n Energy of incident photon is %f eV,which is greater than the work function \n So it causes photoelectric emission.\n Kinetic energy of the emitted electron is %f eV.",E,k)
+