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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1247/CH5/EX5.28/example5_28.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1247/CH5/EX5.28/example5_28.sce')
| -rwxr-xr-x | 1247/CH5/EX5.28/example5_28.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/1247/CH5/EX5.28/example5_28.sce b/1247/CH5/EX5.28/example5_28.sce new file mode 100755 index 000000000..f865e90aa --- /dev/null +++ b/1247/CH5/EX5.28/example5_28.sce @@ -0,0 +1,20 @@ +clear;
+clc;
+
+// Stoichiometry
+// Chapter 5
+// Energy Balances
+
+
+// Example 5.28
+// Page 261
+printf("Example 5.28, Page 261 \n \n");
+
+// solution
+
+lv1 = 26694 // kj/kmol
+Tc = 466.74
+lv2 = lv1*((Tc-298.15)/(Tc-307.7))^.38/1000 // kJ/mol
+Hf = -252 // kJ/mol
+Hf1 = Hf-lv2 // kJ/kmol
+printf("Heat of formation of liquid di ethyl ether = "+string(Hf1)+" kJ/mol.")
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