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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
commit7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
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parentb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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+clc;
+
+d1=100;//mm, diameter of pulley
+d2=50;//mm, diameter of shaft
+us=0.20;// Coeffiecient of static friction between shaft and pully
+W=2.5;//kN , load
+W=W*1000;//N, conversio into N
+//Vertical Force required to raise load
+rf=d2/2*us;//mm, Perpendicular distance from the center Of pully to line of action
+//summing moment about B
+P=W*(d1/2+rf)/(d1/2-rf);//N , downward Force required to raise load
+printf("Force required to raise load is %.0f N in downward direction\n",P);
+
+//Vertcal Force required to hold load
+
+//summing moment about C
+P=W*(d1/2-rf)/(d1/2+rf);//N , downward Force required to hold load
+printf("Force required to hold load is %.0f N in downward direction\n",P);
+
+//Horizontal force P to start raising the load
+OE=rf;//mm,
+OD=sqrt((d1/2)^2+(d1/2)^2);//mm, pythagorus theorm
+theta=asin(OE/OD);//rad,
+
+// from force triangle
+P=W/tan(%pi/4-theta);//N, Horizontal force P to start raising the load
+printf("Horizontal force P required to start raising the load is %.0f N\n",P);
+
+printf("Answer for this example shows variatio , but actual solving gives answers executed by programme\n");