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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc;
+//By theoritical work, applying law of conservation of momentum and energy we get
+//vA=(vB)y=3vc-6, (vB)x=3-vc
+//20*vc^2-78*vc+72=0
+
+y=poly([72,-78,20],'x','coeff');//Obtained polynomial
+vc=roots(y);//m/s,
+vc=vc(1);//AS vc(2) gives negative value of vA
+vA=3*vc-6;// m/s Velocity with which ball A hits the side of table
+vBy=3*vc-6;//m/s, y coefficient Velocity with which ball B hits the side of table
+vBx=3-vc;//m/s, x coefficient Velocity with which ball B hits the side of table
+vB=[vBx,vBy];//m/s Velocity with which ball B hits the side of table
+theta=atan(-vBy/vBx);//rad, angle of velocity B
+theta=theta*180/%pi;//degree
+
+printf("Velocities with which balls hits the sides of table are\n vA= %.1f m/s \n vB= %.3f m/s with theta= %.1f degree \n vC=%.1f m/s\n",vA,norm(vB),theta,vc);