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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 9.35
+clc
+disp("For given DAC, n = 4, V_0FS = +5 V")
+disp("Resolution = V_0FS / 2^n - 1 = 1/3 V/LSB")
+disp("Therefore, V0 = Resolution * D")
+disp("For D = Decimal od 10000 = 8")
+disp(" V0 = 1/3 * 8 = 2.6667 V")
+disp("For D = Decimal of 1111 = 15")
+disp(" V0 = 1/3 * 15 = 5 V")