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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1133/CH3/EX3.7 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1133/CH3/EX3.7')
| -rwxr-xr-x | 1133/CH3/EX3.7/Example3_7.sce | 49 |
1 files changed, 49 insertions, 0 deletions
diff --git a/1133/CH3/EX3.7/Example3_7.sce b/1133/CH3/EX3.7/Example3_7.sce new file mode 100755 index 000000000..cc4a66206 --- /dev/null +++ b/1133/CH3/EX3.7/Example3_7.sce @@ -0,0 +1,49 @@ +//Example 3.7
+clc
+disp("Step 1: Identity topology")
+disp(" By shorting output voltage (Vo = 0), feedback voltage Vf becomes zero and hence it is voltage sampling. The feedback voltage is aaplied in series with input voltage hence the topology is voltage series feedback.")
+disp("")
+disp("Step 2 and Step 3: Find input and output circuit.")
+disp(" To find input circuit, set Vo = 0. This places the parallel combination of resistor 10 K and 200 ohm at first source. To find output circuit, set Ii = 0. This places the resistor 10 K and 200 ohm in series across the output. The resultant circuit is shown in fig.3.50.")
+disp("")
+disp("Step 4: Replace FET with its equivalent circuit as shown in fig.3.51")
+disp("")
+disp("Step 5: Find open loop transfer gain.")
+disp(" Av = Vo / Vs = A_v1*A_v2")
+disp(" A_v2 = -u*R_L2 / R_L2+r_d")
+rl2=(10.2*47)/(10.2+47) // in k-ohm
+format(5)
+disp(rl2,"where R_L2(in k-ohm) =")
+av2=(-40*8.38)/(8.38+10)
+format(7)
+disp(av2,"Therefore, A_v2 =")
+disp(" A_v1 = u*R_Deff / r_d+R_Deff+(1+u)*R_seff")
+rdeff=(47*1000)/(47+1000) // in k-ohm
+format(6)
+disp(rdeff,"where R_Deff(in k-ohm) = R_D || R_G2 =")
+disp(" R_seff = 200 || 10 K")
+av1=(-40*44.98*10^3)/((10*10^3)+(44.89*10^3)+(41*((10*0.2)/(10.2))))
+disp(av1," A_v1 =") // answer in textbook is wrong
+oav=-28.59*-18.237
+format(7)
+disp(oav,"Therefore, Overall Av =")
+disp("")
+disp("Step 6: Calculate beta")
+beta=200/(10.2*10^3)
+disp(beta," beta = Vf / Vo =")
+disp("")
+disp("Step 7: Calculate D, A_vf, R_if, R''_of")
+d=1+(0.0196*521.39)
+format(6)
+disp(d," D = 1 + Av*beta =")
+avf=521.39/11.22
+disp(avf," A_vf = Av / D =")
+disp(" Ri = R_G = 1 M-ohm")
+rif=11.22
+disp(rif," R_if(in M-ohm) = Ri * D =")
+disp(" Ro = r_d = 10 k-ohm")
+ro=(10*8.38)/(18.38) // in k-ohm
+disp(ro," R''o(in k-ohm) = r_d || R_L2 =")
+rof=(4.559*10^3)/11.22 // in ohm
+format(4)
+disp(rof," R''_of(in ohm) = R''o / D =")
\ No newline at end of file |