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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1092/CH8/EX8.20 | |
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Diffstat (limited to '1092/CH8/EX8.20')
| -rwxr-xr-x | 1092/CH8/EX8.20/Example8_20.sce | 56 |
1 files changed, 56 insertions, 0 deletions
diff --git a/1092/CH8/EX8.20/Example8_20.sce b/1092/CH8/EX8.20/Example8_20.sce new file mode 100755 index 000000000..1d5154286 --- /dev/null +++ b/1092/CH8/EX8.20/Example8_20.sce @@ -0,0 +1,56 @@ +// Electric Machinery and Transformers
+// Irving L kosow
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 8: AC DYNAMO TORQUE RELATIONS - SYNCHRONOUS MOTORS
+// Example 8-20
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+f_a = 400 ; // Frequency of the alternator in Hz
+f_m = 60 ; // Frequency of the motor in Hz
+
+// Calculations
+Pole_ratio = f_a / f_m ; // Ratio of no. of poles in alternator to that of motor
+// Subscript 1 below indicates 1st combination
+P_a1 = 40 ; // first combination must have 40 poles on the alternator
+P_m1 = 6 ; // first combination must have 6 poles on the synchronous motor at a speed
+S_m1 = (120*f_m) / P_m1 ; // Speed of the motor in rpm
+
+// Subscript 2 below indicates 2nd combination
+P_a2 = 80 ; // second combination must have 40 poles on the alternator
+P_m2 = 12 ; // second combination must have 12 poles on the synchronous motor at a speed
+S_m2 = (120*f_m) / P_m2 ; // Speed of the motor in rpm
+
+// Subscript 13below indicates 3rd combination
+P_a3 = 120 ; // third combination must have 40 poles on the alternator
+P_m3 = 18 ; // third combination must have 18 poles on the synchronous motor at a speed
+S_m3 = (120*f_m) / P_m3 ; // Speed of the motor in rpm
+
+// Display the result
+disp("Example 8-20 Solution : ");
+
+printf(" \n Since P_a/P_m = f_a/f_m = %d/%d, or %d/%d, the ratio of",f_a,f_m,f_a/20,f_m/20);
+printf(" \n f_a/f_m determines the combinations of poles and speed.\n");
+printf(" \n Only even multiples of the above ratio are possible,since poles ");
+printf(" \n are always in pairs, hence first three combinations are as follows \n");
+
+printf(" \n The first combination must have %d poles on the alternator and ",P_a1);
+printf(" \n %d poles on the sychronous motor at a speed = %d rpm.\n",P_m1,S_m1);
+
+printf(" \n The second combination must have %d poles on the alternator and ",P_a2);
+printf(" \n %d poles on the sychronous motor at a speed = %d rpm.\n",P_m2,S_m2);
+
+printf(" \n The third combination must have %d poles on the alternator and ",P_a3);
+printf(" \n %d poles on the sychronous motor at a speed = %d rpm.\n",P_m3,S_m3);
+
+printf(" \n ___________________________________________________________________");
+printf(" \n Combination \t Alternator Poles \t Motor Poles \t Speed (rpm)");
+printf(" \n \t P_a \t P_m \t S ");
+printf(" \n ___________________________________________________________________");
+printf(" \n First \t\t:\t %d\t\t %d \t %d",P_a1,P_m1,S_m1);
+printf(" \n Second\t\t:\t %d\t\t %d \t %d",P_a2,P_m2,S_m2);
+printf(" \n Third \t\t:\t %d\t\t %d \t %d",P_a3,P_m3,S_m3);
+printf(" \n ___________________________________________________________________");
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