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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+l=3;
+r=.25e-2;
+rho=100;
+h=.5;
+
+//(a)
+Ra=(rho/(%pi * l)) *(log(2*l/r)-1);
+mprintf("\n (a) Resistance when buried at surface of earth = %.2f ohm", Ra)
+
+//(b)
+Rb=(rho/(%pi * l)) *(log(2*l/sqrt(2*r*h))-1);
+mprintf("\n (a) Resistance when buried .5m under earth earth = %.2f ohm", Rb)
+
+//(c)
+Rc=Ra/2
+mprintf("\n (c) Resistance when buried infinte deep = %.2f ohm", Rc)
+