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authorpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+//Example 6.10
+Ts=381.3 //[K]
+dT=56.6; //[K]
+U1=2800; //Overall heat transfer coeff in first effect
+U2=2200; //Overall heat transfer coeff in first effect
+U3=1100; //Overall heat transfer coeff in first effect
+dT1=dT/(1+(U1/U2)+(U1/U3)) ///[K]
+dT2=dT/(1+(U2/U1)+(U2/U3)) ///[K]
+dT3=dT-(dT1+dT2) //[K]
+//dT1=Ts-T1_dash //[K]
+T1dash=Ts-dT1
+//dT2=T1_dash-T2_dash //[K]
+T2_dash=T1dash-dT2 //[K]
+printf("\n\nBoiling point of solution in first effect =%f K\n\n",T1dash);
+printf("\n\nBoiling point of solution in second effect =%f K\n\n",T2_dash);
+