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authorpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+//Example 3.7
+rho=0.998 //kg/cubic m
+v=20.76*10^-6 //[sq m/s]
+Cp=1.009 //[kJ/kg.K]
+k=0.03 //[W/m.K]
+u_inf=3 //[m/s]
+x=0.4 //[m]
+w=1.5 //[m]
+Nre_x=u_inf*x/v //Reynolds no at x=0.4 m
+//Since this is less than 3*10^5.The flow is laminar upto x=0.4 m
+mu=rho*v //[kg/(m.s)]
+
+Cp=1.009 //[kJ/kg.K]
+Cp=Cp*1000 //[J/kg.K]
+k=0.03 //W/(m.K)
+Npr=Cp*mu/k
+Nnu_x=0.332*(sqrt(Nre_x))*(Npr^(1.0/3.0))
+hx=Nnu_x*k/x //[W/(m.K)]
+//Average value is twice this value
+h=2*hx //[W/(m.K)]
+h=10.6 //Approximation
+A=x*w //Area in [sq m]
+Tw=407 //[k]
+T_inf=293 //[K]
+Q=h*A*(Tw-T_inf) //[W]
+//From both sides of the plate:
+Q=2*Q //[W]
+printf("The heat transferred from both sides of the plate is %d W",round(Q));
+
+