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authorpriyanka2015-06-24 15:03:17 +0530
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+
+clc;
+clear;
+//Example 3.34
+rho=960.63 //Density in [kg/m^3]
+Cp=4.216*10^3 //Specific heat in [J/(kg.K)]
+D=16 //Diameter in [cm]
+D=D/100 //[m]
+k=0.68 //Thermal conductivity in [W/m.K]
+A=(%pi*(D/2)^2)
+L=A/(%pi*D) //Length=A/P in [m]
+Beta=0.75*10^-3 //[K^-1]
+alpha=1.68*10^-7 //[m^2/s]
+g=9.81 //[m/s^2]
+Tw=403 //[K]
+T_inf=343 //[K]
+dT=Tw-T_inf //[K]
+v=0.294*10^-6 //[m^2/s]
+Nra=(g*Beta*(L^3)*dT)/(v*alpha)
+
+//1.For Top surface
+Nnu=0.15*(Nra)^(1.0/3.0) //Nusselt number
+ht=Nnu*k/L //Heat transfer coeff for top surface in W/(m^2.K)
+ht=round(ht)
+//2.For bottom surface
+Nnu=0.27*Nra^(1.0/4.0) //Nusselt number
+hb=Nnu*k/L //[W/sq m.K]
+hb=round(hb)
+Q=(ht+hb)*A*dT; //[W]
+printf("The rate of heat input is %f W",Q)
+