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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc;
+clear;
+printf("Example 2.24\n Page no. 2.47");
+//given
+L=1//m
+thp=2//Thickness of pipe; in mm
+thi=10//Thickness of insulation; in mm
+T1=373//K
+T2=298//K
+id=30//mm
+r1=id/2//mm
+r2=r1+thp//mm
+r3=r2+thi//mm
+//In S.I units
+r1=r1/1000 //m
+r2=r2/1000//m
+r3=r3/1000//m
+k1=17.44//W/(m.K)
+k2=0.58//W/(m.K)
+hi=11.63//W/(sq m.K)
+ho=11.63//W/(sq m.K)
+//Solution
+Q=(2*%pi*L*(T1-T2))/(1/(r1*hi)+(log(r2/r1))/k1+((log(r3/r2))/k2)+(1/(0.02*ho)))
+printf("ANSWER: \n Rate of heat loss,Q=%f W",Q);