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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
commitb1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch)
treeab291cffc65280e58ac82470ba63fbcca7805165 /1055/CH13/EX13.4/ch13_4.sce
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+//Determine the fault current and line to line voltage at the fault .
+clear
+clc;
+Ea=1;
+L=(cosd(120)+ %i*sind(120));
+Z1=%i*.25;
+Z2=%i*.35;
+Ia1=Ea/(Z1+Z2);
+Ia2=-Ia1;
+Iao=0;
+Ib1=(L^2)*Ia1;
+Ib2=L*Ia2;
+Ibo=0;
+Ib=Ib1+Ib2 +Ibo;
+Iba=1093;
+If=Iba*abs(Ib);
+Va1=Ea-(Ia1*Z1);
+Va2=-Ia2*Z2;
+Vao=0;
+Va=Va1+Va2+Vao;
+Vb=(L^2)*Va1 + L*Va2;
+Vc=Vb;
+Vab=Va-Vb;
+Vac=Va-Vc;
+Vbc=Vb-Vc;
+mprintf("Fault current =%.2f amps\n",If);//Answer don't match due to difference in rounding off of digits
+vab=(abs(Vab)*13.2)/sqrt(3);
+vbc=(abs(Vbc)*13.2)/sqrt(3);
+vac=(abs(Vac)*13.2)/sqrt(3);
+mprintf("Vab=%.2f kV\n",vab);
+mprintf("Vac=%.2f kV\n",vac);
+mprintf("Vbc=%.2f kV\n",vbc);