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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1052/CH16/EX16.2 | |
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initial commit / add all books
Diffstat (limited to '1052/CH16/EX16.2')
-rwxr-xr-x | 1052/CH16/EX16.2/162.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/1052/CH16/EX16.2/162.sce b/1052/CH16/EX16.2/162.sce new file mode 100755 index 000000000..8ad5a6f30 --- /dev/null +++ b/1052/CH16/EX16.2/162.sce @@ -0,0 +1,21 @@ +clc;
+//Example 16.2
+//page no 183
+printf(" Example 16.2 page no 183\n\n");
+//cal. pressure drop if the flow for both phases is turbulent
+//a. since the flow is tt and 1<X<10 ,apply equatuion 16.16b to obtain Y_g
+X=1.66
+Y_g=5.80+6.7143*X+6.9643*X^2-0.75*X^3
+printf("\n Y_g=%f ",Y_g);
+//the value of Y_g is an excellent agreement with the values provided by lockhart and Martinelli
+//then pressure drop is
+P_drop_g=2.71
+P_drop_t=Y_g*P_drop_g
+printf("\n P_drop_t=%f psf/100 ft",P_drop_t);
+//b. applying eq. 16.17b to generate Y_l
+Y_l=18.219*X^-.8192
+printf("\n Y_l =%f ",Y_l);
+//pressure drop from eq. 16.2
+P_drop_l=7.50
+P_drop=Y_l*P_drop_l
+printf("\n P_drop=%f psf/100ft",P_drop);
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