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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1019/CH8/EX8.2/Example_8_2.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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Diffstat (limited to '1019/CH8/EX8.2/Example_8_2.sce')
| -rw-r--r-- | 1019/CH8/EX8.2/Example_8_2.sce | 27 |
1 files changed, 27 insertions, 0 deletions
diff --git a/1019/CH8/EX8.2/Example_8_2.sce b/1019/CH8/EX8.2/Example_8_2.sce new file mode 100644 index 000000000..9bd8c3d3f --- /dev/null +++ b/1019/CH8/EX8.2/Example_8_2.sce @@ -0,0 +1,27 @@ +//Example 8.2
+clear;
+clc;
+
+//Given
+p=0.35;
+Kp=p*10^-24;//equillibrium constant at 300K
+P0=1.0;//standard pressure in atm
+T=300;//Temperature in K
+R=0.082;// gas constant in atm dm^3 mol^-1K^-1
+C0=1;//in mol/dm^3
+Kp2=0.157;//Kp for reaction in (b)
+P=1;//pressure in atm
+
+// (a) To determine Kc1
+delv=(2+1)-2;
+c=p*((P0/(C0*R*T)))^delv
+Kc1=c*10^-24;//equillibrium constant
+mprintf('(a) Kc = %f *(10^-24)',c);
+
+//(b) To determine Kc2
+delv2=2-1;
+Kc2=Kp2*((P0/(C0*R*T)))^delv2;
+mprintf('\n (b) Kc = %f',Kc2);
+Kx=Kp2*(P0/P);//equillibrium constant
+mprintf('\n Kx = %f',Kx)
+//end
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