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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1019/CH8/EX8.1 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '1019/CH8/EX8.1')
| -rw-r--r-- | 1019/CH8/EX8.1/Example_8_1.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/1019/CH8/EX8.1/Example_8_1.sce b/1019/CH8/EX8.1/Example_8_1.sce new file mode 100644 index 000000000..a1e003f90 --- /dev/null +++ b/1019/CH8/EX8.1/Example_8_1.sce @@ -0,0 +1,18 @@ +//Example 8.1
+clear;
+clc;
+
+//Given
+Kp=0.10;//equillibrium constant at 300K
+Pa=20;// Partial pressure of A in atm
+Pm=1.0;///partial pressure of M in atm
+T=300;//Temperature in K
+R=8.314;// gas constant in J K^-1 mol^-1
+//To determine the free energy
+Qp=Pm/Pa;//reaction quotient
+delG=R*T*log(Qp/Kp);//free energy change
+mprintf('(a) delG = %f J mol^-1',delG);
+delG0=-R*T*log(Kp);//standard free energy in J mol^-1
+mprintf('\n (b) standard free energy = %f J mol^-1',delG0);
+mprintf('\n (c) Since delG is negetive,the reaction proceeds spontaneously in forward direction')
+//end
\ No newline at end of file |