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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1019/CH5/EX5.20/Example_5_20.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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-rw-r--r-- | 1019/CH5/EX5.20/Example_5_20.sce | 16 |
1 files changed, 16 insertions, 0 deletions
diff --git a/1019/CH5/EX5.20/Example_5_20.sce b/1019/CH5/EX5.20/Example_5_20.sce new file mode 100644 index 000000000..5a49afdc4 --- /dev/null +++ b/1019/CH5/EX5.20/Example_5_20.sce @@ -0,0 +1,16 @@ +//Example 5.20
+clear;
+clc;
+
+//Given
+delHf=335;//latent heat of fusion in J g^-1
+Vs=1.0908;//volume of solid in cm^3 g^-1
+Vl=1.0002;//volume of liquid in cm^3 g^-1
+T=273;//temperature in K
+
+//To determine the decrease in melting point with increase in pressure
+delVm=Vl-Vs;//volume change in cm^3 g^-1
+a=(delHf*10)/(T*delVm*1.01325);//a=(delP/delT)
+b=a^(-1);//b=(delT/delP)
+mprintf('An increase in pressure of 1 atm lowers the freezing point by %f K atm^-1',b);
+//end
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