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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 4.6
+clear;
+clc;
+
+//Given
+R=8.314;// gas constant in J K^-1 mol^-1
+Cv=20.8; //specific heat capacity at constant volume of the gas in J K^-1 mol^-1
+w=0.1;//weight of the gas in kg
+T1=298; //initial temperature in K
+P1=30;//initial pressure in atm
+P2=10;//final pressure in atm
+
+//to calculate the entropy
+Cp=Cv+R;//specific heat capacity at constant pressure of the gas in J K^-1 mol^-1
+n=(w*1000)/28;//moles
+T2=T1*((Cv+(R*(P2/P1)))/Cp);//final temperature in K
+r=(P1*T2)/(T1*P2);//r=V2/V1
+delS=(n*Cv*log(T2/T1))+(n*R*log(r));//entropy change in J K^-1
+mprintf('Entropy of the system = %f J K^-1',delS);
+mprintf('\n final temperature = %f K',T2);
+//end \ No newline at end of file