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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Example 2.21
+clear;
+clc;
+
+//Given
+T1=300; //initial temperature in K
+T2=600; //final temperature in K
+R=8.314;// gas constant in J K^-1 mol^-1
+Cv=25; //specific heat capacity at constant volume of the gas in J K^-1 mol^-1
+n=1;//moles of the gas
+P1=100; //initial gas pressure in kN m^-2
+P2=1000; //final gas pressure in kN m^-2
+
+// To determine net work done and efficiency
+w1=R*T1*log(P2/P1);//work done in 1st step in J
+w2=Cv*(T2-T1);//work done in 2nd step in J
+w3=R*T2*log(P1/P2);//work done in 3rd step in J
+q2=(-1)*w3;//heat taken up in J
+w4=Cv*(T1-T2);//work done in final step in J
+W=-(w1+w2+w3+w4);//total work done step in J
+N=W/q2;//efficiency
+mprintf('Net work done = %f',W);
+mprintf('\n Heat absorbed = %f',q2);
+mprintf('\n efficiency = %f',N);
+//end \ No newline at end of file