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{
"metadata": {
"name": "",
"signature": "sha256:60b1203d60983bbbb28528cd720bc31b7ac71ec9fc83b7d2e5e78e90b9f2b472"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter1-Introduction"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg32"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"\n",
"#calculate the steady state\n",
"\n",
"\n",
"##The thickness of the slab(L) is 80mm or .08m\n",
"##The thermal conductivity(k)of the material is .20 W/(m*K)\n",
"T1=40.;\n",
"T2=20.;\n",
"L=.08;\n",
"k=.20;\n",
"##The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L\n",
"print(\"The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \")\n",
"q=k*(T1-T2)/L\n",
"print(q)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \n",
"50.0\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg32"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"#calculate the thickness of masonry wall\n",
"print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\")\n",
"##The thermal conductivity(km)of masonry wall is .8 W/(mK)\n",
"##The thermal conductivity(kc)of composite wall is .2 W/(mK)\n",
"##The thickness of composite wall(Lc) is 100 mm or .1 m\n",
"km=.8;\n",
"kc=.2;\n",
"Lc=.1;\n",
"##The thickness of masonry wall(Lm) is to be found. \n",
"##The steady state heat flow(qm)through masonry wall is km(T1-T2)/L\n",
"## The steady state heat flow(qc)through composite wall is kc(T1-T2)/L\n",
"##As the steady rate of heat flow through masonry wall is 80% that through composite wall and both the wall have same surface area and same temp. difference so qm/qc=0.8=(km/kc)*(Lc/Lm)\n",
"##The thickness of masonry wall is Lm.\n",
"print (\"The thickness of masonry wall is Lm in m\")\n",
"Lm=(km/kc)*(Lc/(0.8))\n",
"print(Lm)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\n",
"The thickness of masonry wall is Lm in m\n",
"0.5\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg36"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"## printlay warning for floating point exception\n",
"print(\"Introduction to heat transfer by S.K.Som Chapter 1 Example 4\")\n",
"hbr=200.;\n",
"Tinf=100.;\n",
"Ts=20.;\n",
"##The rate of heat transfer per unit area is q\n",
"print (\"The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\")\n",
"q=hbr*(Tinf-Ts)\n",
"print(q)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Introduction to heat transfer by S.K.Som Chapter 1 Example 4\n",
"The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\n",
"16000.0\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex5-pg36"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"#calculat e surface area\n",
"print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\")\n",
"\n",
"hbr=800.;\n",
"deltaT=(75.-25.);\n",
"Q=20.;\n",
"print(\"The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \")\n",
"A = (Q*10**6.)/(3600.*hbr*deltaT)\n",
"print round(A,2)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\n",
"The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \n",
"0.14\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex6-pg37"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##The ambient temprature (Tinf) \n",
"print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\")\n",
"Ts=225.;\n",
"Tinf=25.;\n",
"## |because it is modulus function and it converts negative values to positive value.\n",
"X=0.02;\n",
"A=.1;\n",
"m=4;\n",
"cp=2.8;\n",
"hbr=(m*cp*10**3*X)/(A*(Ts-Tinf))\n",
"print round(hbr,2)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\n",
"11.2\n"
]
}
],
"prompt_number": 8
}
],
"metadata": {}
}
]
}
|
