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{
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"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter2-Nuclear Engineering"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg54"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"## Example 2.1\n",
"import math\n",
"#determine atoms in deuterium\n",
"## Given data\n",
"atom_h = 6.6*10**24; ## Number of atoms in Hydrogen\n",
"## Using the data given in Table II.2, Appendix II for isotropic abundance of deuterium\n",
"isoab_H2 = 0.015; ## Isotropic abundance of deuterium\n",
"## Calculation\n",
"totatom_d=(isoab_H2*atom_h)/100.;\n",
"## Result\n",
"print\"%s %.2e %s \"%('\\n Number of deuterium atoms = ',totatom_d,'');\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
" Number of deuterium atoms = 9.90e+20 \n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg54"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"## Example 2.2\n",
"import math\n",
"#determine atomic weight of oxygen\n",
"## Given data \n",
"## Using the data given in the example 2.2\n",
"atwt_O16 = 15.99492; ## Atomic weight of O-16 isotope\n",
"isoab_O16 = 99.759; ## Abundance of O-16 isotope\n",
"atwt_O17 = 16.99913; ## Atomic weight of O-17 isotope\n",
"isoab_O17 = 0.037; ## Abundance of O-17 isotope\n",
"atwt_O18 = 17.99916; ## Atomic weight of O-18 isotope\n",
"isoab_O18 = 0.204; ## Abundance of O-18 isotope\n",
"## Calculation\n",
"atwt_O=(isoab_O16*atwt_O16 + isoab_O17*atwt_O17 + isoab_O18*atwt_O18)/100.;\n",
"## Result\n",
"print\"%s %.2f %s \"%('\\n Atomic Weight of Oxygen = ',atwt_O,'');\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
" Atomic Weight of Oxygen = 16.00 \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg55"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"## Example 2.3\n",
"import math\n",
"#determine rest mass energy of electron\n",
"## Given data\n",
"me = 9.1095*10**(-28); ## Mass of electron in grams\n",
"c = 2.9979*10**10; ## Speed of light in vacuum in cm/sec\n",
"## Calculation\n",
"rest_mass = me*c**2;\n",
"## Result\n",
"print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass,' ergs\\n');\n",
"print('Expressing the result in joules')\n",
"## 1 Joule = 10^(-7)ergs\n",
"rest_mass_j = rest_mass*10**(-7);\n",
"print\"%s %.2e %s \"%('\\n Rest mass energy of electron = ',rest_mass_j,' joules\\n');\n",
"print('Expressing the result in MeV')\n",
"## 1 MeV = 1.6022*10^(-13)joules\n",
"rest_mass_mev = rest_mass_j/(1.6022*10**(-13));\n",
"print\"%s %.2f %s \"%('\\n Rest mass energy of electron = ',rest_mass_mev,' MeV\\n');\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
" Rest mass energy of electron = 8.19e-07 ergs\n",
" \n",
"Expressing the result in joules\n",
"\n",
" Rest mass energy of electron = 8.19e-14 joules\n",
" \n",
"Expressing the result in MeV\n",
"\n",
" Rest mass energy of electron = 0.51 MeV\n",
" \n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}
|
