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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter1-Fundamental Concepts"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg21"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Chapter 1, Example 1.1, Page 21\n",
"import math\n",
"##Find Atomic weight of Boron\n",
"I10 = 0.199 ## Isotopic abundance of B10 (Value used in question is wrong)\n",
"A10 = 10.012937 ##Atomic weight of B10\n",
"I11 = 0.801 ## Isotopic abundance of B11\n",
"A11 = 11.009306 ##Atomic weight of B11\n",
"##Calculation\n",
"W = (I10*A10)+(I11*A11)\n",
"print'%s %.2f %s'%(\"The atomic weight of Boron = \",W,\"\");\n",
"\n",
"##Answers may vary due to round off error\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The atomic weight of Boron = 10.81 \n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg22"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Chapter 1, Example 1.2, Page 22\n",
"import math\n",
"##Find number of 10B molecules in 5g of Boron\n",
"m = 5. ##g\n",
"Na = 0.6022*10**24 ##atoms/mol\n",
"AB = 10.811 ##Atomic weight of 10B , g/mol\n",
"NB = (m*Na)/(AB)\n",
"print'%s %.2e %s'%(\"The number of Boron atoms = \",NB,\" atoms\");\n",
"\n",
"##Answers may vary due to round off error\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The number of Boron atoms = 2.79e+23 atoms\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg22"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Chapter 1, Example 1.3, Page 22\n",
"import math\n",
"##Estimate the mass on an atom of U 238. From Eq. (1.3)\n",
"##Calculating the approximate weight\n",
"Mapprox = 238./(6.022*10**23)\n",
"##Calculating the precise weight\n",
"M = 238.050782/(6.022142*10**23)\n",
"print'%s %.2e %s'%(\"The approximate mass on an atom of U 238 = \",Mapprox,\" g/atom\");\n",
"print'%s %.2e %s'%(\"\\n The precise mass on an atom of U 238 = \",M,\" g/atom\")\n",
"print(\"Varies by a negligible error\")\n",
"##Answers may vary due to round off error\n",
"\n",
" \n",
" \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The approximate mass on an atom of U 238 = 3.95e-22 g/atom\n",
"\n",
" The precise mass on an atom of U 238 = 3.95e-22 g/atom\n",
"Varies by a negligible error\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg23"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Chapter 1, Example 1.4, Page 23\n",
"import math\n",
"##Density of Hydrogen atom in water\n",
"p = 1. ## density of water in g cm^-3\n",
"Na = 6.022*10**23 ## molucules/mol\n",
"A = 18. ## atomic weight of water in g/mol\n",
"N = (p*Na)/A\n",
"NH = 2.*N\n",
"print'%s %.2e %s'%(\"The density of water = \",N,\" molecules/cm3\");\n",
"print'%s %.2e %s'%(\"\\n The density of hydrogen atoms = \",NH,\" atoms/cm3\");\n",
"##Answers may vary due to round off error\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The density of water = 3.35e+22 molecules/cm3\n",
"\n",
" The density of hydrogen atoms = 6.69e+22 atoms/cm3\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}
|
