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{
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{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 1: Interference"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.7, Page number 1-19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"#Given Data:\n",
"i=30 #angle of incidence\n",
"u=1.43 #Refractive index of a soap film\n",
"lamda=6*10**-7 #wavelength of light\n",
"n=1 #For minimum thickness\n",
"\n",
"#Calculations:\n",
"#u=sin i/sin r #Snell's law .So,\n",
"r=math.degrees(math.asin(math.sin(i)/u)) #angle of reflection\n",
"\n",
"#Now, condition of minima in transmitted system is\n",
"#2ut*cos(r)=(2n-1)lam/2\n",
"t=lamda/(2*2*u*math.cos(r)) #minimum thickness of film\n",
"print\"Minimum thickness of film is \",t,\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Minimum thickness of film is 1.09096619878e-07 m\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 1.8, Page number 1-19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#Given Data:\n",
"\n",
"lamda = 5893*10**-10 #Wavelength of light\n",
"theta = 1 #assuming value of theta\n",
"\n",
"#We know, B=lam/(2*u*theta). Here u=1\n",
"B = lamda/(2*theta) #fringe spacing\n",
"n=20 #interference fringes\n",
"\n",
"#Calculations:\n",
"#t=n*B*tan(theta)\n",
"t = 20*B*theta #Thickness of wire\n",
"print\"Thickness of wire is =\",t,\"m\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Thickness of wire is = 5.893e-06 m\n"
]
}
],
"prompt_number": 18
}
],
"metadata": {}
}
]
}
|
