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{
"metadata": {
"name": "",
"signature": "sha256:a1991f0c2ad3cdd162c5a3598633b434636cdfbb3e50ee12bef51cec75158259"
},
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 1 - Differential Amplifiers"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exa 1.8 - pg:19"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given data\n",
"BETAac=100 #unitless\n",
"BETAdc=100 #unitless\n",
"VBE3=0.715 #in volts\n",
"VD1=0.715 #in Volts\n",
"VZ=6.2 #in Volts\n",
"VT=25 #in mVolts\n",
"IZt=41 #in mA \n",
"VCC=10 #in Volts\n",
"VEE=-10 #in Volts\n",
"RC1=2.7 #in kohm\n",
"RC=4.7 #in kohm\n",
"#Part (a)\n",
"VB3=VEE+VZ+VD1 #in volts\n",
"VE3=VB3-VBE3\n",
"IE3=(VE3-VEE)/RC1 #in mA\n",
"#As the differential amplifier is symmetrical, ICQ1=IE1=ICQ2=IE2\n",
"IE2=IE3/2 #in mA\n",
"ICQ1=IE2 #in mA\n",
"ICQ2=IE2 #in mA\n",
"IE1=IE2 #in mA\n",
"VCEQ=VCC+VBE3-RC*ICQ1# formula for VCEQ \n",
"print \"Operating point for Q1 and Q2 are : \"\n",
"print \"VCEQ is \",round(VCEQ,2),\" V\"\n",
"print \"ICQ is \",round(ICQ1,2),\" mA\"\n",
"print \"and the operating point for Q3 will be : \"\n",
"VCE3=-VBE3-VE3 #in Volts\n",
"print \"VCE3 is \",round(VCE3,2),\" V\"\n",
"IC3=IE3 #in mA\n",
"print \"IE3 is \",round(IE3,2),\" mA\"\n",
"#Part (b)\n",
"re=(2*VT)/IC3 #in ohm\n",
"Ad=(RC*1000)/re #unitless\n",
"print \"Differential voltage gain is \",round(Ad,2)\n",
"#Part (c)\n",
"Ri=2*BETAac*re #in ohm\n",
"Ri/=1000 # kohm\n",
"print \"Input resistance is \",round(Ri,2),\" kohm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Operating point for Q1 and Q2 are : \n",
"VCEQ is 5.32 V\n",
"ICQ is 1.15 mA\n",
"and the operating point for Q3 will be : \n",
"VCE3 is 3.08 V\n",
"IE3 is 2.3 mA\n",
"Differential voltage gain is 215.85\n",
"Input resistance is 4.35 kohm\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exa 1.9 : pg-29"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given data\n",
"Io=180 #in uA\n",
"Vcc=20 #in Volts\n",
"VBE=0.7 #in Volts\n",
"BETA=120 #unitless\n",
"IR=Io*(1+2/BETA) #in uA\n",
"R=(Vcc-VBE)/(IR*10**-3) #in kohm\n",
"print \"Value of IR is \",round(IR,2),\" uA\"\n",
"print \"Value of R is \",round(R,2),\" kohm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Value of IR is 180.0 uA\n",
"Value of R is 107.22 kohm\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exa 1.16 : pg-31"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given data\n",
"BETAac=100 #unitless\n",
"BETAdc=100 #unitless\n",
"VBEon=0.7 #in volts\n",
"VCC=5 #in volts\n",
"VEE=-5 #in volts\n",
"VT=25 #in mVolts\n",
"R=18.6 #in kohm\n",
"Ad=200 #unitless\n",
"IR=(VCC-VBEon -VEE)/R #in mA\n",
"IC1=IR/2 #in mA\n",
"IC2=IC1 #in mA\n",
"re1=(2*VT)/IR #in ohm\n",
"re2=re1 #in ohm\n",
"RC=Ad*re1*10**-3 #in kohm\n",
"print \"Rc is \",round(RC,2),\" kohm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Rc is 20.0 kohm\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exa 1.18 : pg-33"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given data\n",
"Iload=20 #in uA\n",
"VBE=0.7 #in volts\n",
"VCC=10 #in Volts\n",
"IR=Iload #in mA\n",
"R=(VCC-2*VBE)/(IR*10**-3) #in kohm\n",
"print \"R is \",round(R,2),\" kohm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"R is 430.0 kohm\n"
]
}
],
"prompt_number": 22
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Exa 1.23 : pg-26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given data\n",
"Vo=5 #in volts\n",
"BETAac=150 #unitless\n",
"BETAdc=150 #unitless\n",
"VT=25 #in mV\n",
"VCC=10 #in mV\n",
"VD=0.7 #in mV\n",
"R1=2.7 #in kohm\n",
"R2=1.5 #in kohm\n",
"# part (i) #\n",
"# IC1/IC2=exp((VBE1-VBE2)/VT)\n",
"# Writing KVL for the loop\n",
"IR=(VCC-VD)/R1 #in mA\n",
"IC=(IR-VD/R2)/(1+2/BETAac) #in mA\n",
"IC1=IC #in mA\n",
"IC2=IC #in mA\n",
"RC=(VCC-Vo)/IC #in kohm\n",
"print \"IC1 is \",round(IC1,2),\" mA\"\n",
"print \"IC2 is \",round(IC2,2),\" mA\"\n",
"print \"RC is \",round(RC,2),\" kohm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"IC1 is 2.98 mA\n",
"IC2 is 2.98 mA\n",
"RC is 1.68 kohm\n"
]
}
],
"prompt_number": 17
}
],
"metadata": {}
}
]
}
|
