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{
 "metadata": {
  "name": ""
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 1: Basic Ideas: Energy Bands in Solids"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 1, Page 8"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#Variable decalaration\n",
      "pd = 100   #potential difference, V\n",
      "m0=9.11*(10**-31);#m0=rest mass of the electron in kg\n",
      "\n",
      "#Calculations&Results\n",
      "#solving final velocity of the electron\n",
      "Ek=1.6*(10**-19)*pd;#Ek=final kinetic energy of electron in Joules\n",
      "print \"Final kinetic energy = %.1e J,%.f eV\"%(Ek,Ek*6.242*10**18)\n",
      "v=math.sqrt((2*Ek)/m0)#v=final velocity of the electron\n",
      "print \"Final velocity = %.3e m/s\"%v"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Final kinetic energy = 1.6e-17 J,100 eV\n",
        "Final velocity = 5.927e+06 m/s\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 2, Page 8"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "\n",
      "#Variable declaration\n",
      "m=7360*9.11*(10**-31);#m=mass of the ion in kg\n",
      "q=2*1.6*(10**-19);#q=charge of the ion in Coulomb\n",
      "V=2000;#V=potential difference in Volt\n",
      "\n",
      "#Calculations&Results\n",
      "#solving velocity & kinetic energy of the ion\n",
      "v=math.sqrt((2*q*V)/m)#v=velocity of the ion\n",
      "print \"Velocity acquired by the ion = %.3e m/s\"%v\n",
      "Ek=(1./2)*m*(v**2)#Ek=kinetic energy of the ion\n",
      "print \"Kinetic energy of ion = %.1e J = %.f eV\"%(Ek,Ek*6.242*10**18)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Velocity acquired by the ion = 4.369e+05 m/s\n",
        "Kinetic energy of ion = 6.4e-16 J = 3995 eV\n"
       ]
      }
     ],
     "prompt_number": 2
    }
   ],
   "metadata": {}
  }
 ]
}